3+
H is +1, O is -2 overall carbon will have an oxidation # of -3
The oxidation number of carbon (C) in CH2O is +2. This is because hydrogen (H) has an oxidation number of +1 and oxygen (O) has an oxidation number of -2, so the sum of the oxidation numbers in CH2O must be zero to balance the charge.
The oxidation number of C in C₂O₄ is +3. Each oxygen atom carries a charge of -2, and since there are 4 oxygen atoms in total with a total charge of -8, the carbon atom's oxidation number must be +3 to balance the charges in the compound.
The oxidation number for carbon (C) in carbon dioxide (CO2) is +4. Each oxygen atom has an oxidation number of -2, so in the compound CO2, the total oxidation number must equal 0.
The oxidation number of C in CO3^2- is +4. Each oxygen atom has an oxidation number of -2, and since the overall charge of the carbonate ion is 2-, the carbon atom must have an oxidation number of +4 to balance the charge.
H is +1, O is -2 overall carbon will have an oxidation # of -3
The oxidation number of carbon (C) in CH2O is +2. This is because hydrogen (H) has an oxidation number of +1 and oxygen (O) has an oxidation number of -2, so the sum of the oxidation numbers in CH2O must be zero to balance the charge.
The oxidation number of C in C₂O₄ is +3. Each oxygen atom carries a charge of -2, and since there are 4 oxygen atoms in total with a total charge of -8, the carbon atom's oxidation number must be +3 to balance the charges in the compound.
The oxidation number for carbon (C) in carbon dioxide (CO2) is +4. Each oxygen atom has an oxidation number of -2, so in the compound CO2, the total oxidation number must equal 0.
The oxidation number is + for C and -2 for O.
The oxidation number of C in CO3^2- is +4. Each oxygen atom has an oxidation number of -2, and since the overall charge of the carbonate ion is 2-, the carbon atom must have an oxidation number of +4 to balance the charge.
+2 for Mg +4 for C -2 for each O
It depends on what form it is in. It can be in the 4+ oxidation state, 4- oxidation state and every oxidation state in between.
The oxidation number of Ca is 0 in its elemental form and is +2 in its compounds.
C2O42-COO -lCOO -O always has an oxidation states of -2.So if there are 4 O atoms, with -2 each, it gives a total of -8.since the charge on the ion is -2, the total carbon is +6, and there are 2, so each carbon is +3.C= +3
CO is a harmful gas.C shows +2 in CO and it shows +4 in CO2.
In KO2, O has an oxidation number of -1, K has an oxidation number of +1. In CO2, O has an oxidation number of -2, C has an oxidation number of +4. In K2CO3, O has an oxidation number of -2, C has an oxidation number of +4, and K has an oxidation number of +1. In the given reaction, the oxidation numbers for each atom remain the same as in their individual compounds.