To determine the oxidation state of carbon in organic compounds, one can count the number of bonds carbon forms with more electronegative elements like oxygen, nitrogen, or halogens. The oxidation state of carbon is equal to the number of bonds it forms minus the number of bonds it would form in a neutral state.
In SO3^2-, sulfur has an oxidation state of +4 (Sulfur's typical oxidation state is +6 and each oxygen has an oxidation state of -2, so the total charge of the ion of -2 corresponds to sulfur being in a +4 oxidation state).
H2SO4 is a compound and as such does not have an oxidation number. The individual atoms in this compound have oxidation number +1 for each hydrogen atom, +6 for sulfur, and -2 for each oxygen atom.
Minus one for hydroxyl ( -OH) groups, minus two for oxo ( =O) groups.
In the compound Al2O3 oxygen is oxidized to minus 2. You will note that two aluminum times plus 3 is 6, and 3 oxygen times minus 2 is minus 6; thus the combination of aluminum and oxygen yields an electrically neutral molecule, since 6 - 6 = 0.
To determine the oxidation state of carbon in organic compounds, one can count the number of bonds carbon forms with more electronegative elements like oxygen, nitrogen, or halogens. The oxidation state of carbon is equal to the number of bonds it forms minus the number of bonds it would form in a neutral state.
In SO3^2-, sulfur has an oxidation state of +4 (Sulfur's typical oxidation state is +6 and each oxygen has an oxidation state of -2, so the total charge of the ion of -2 corresponds to sulfur being in a +4 oxidation state).
H2SO4 is a compound and as such does not have an oxidation number. The individual atoms in this compound have oxidation number +1 for each hydrogen atom, +6 for sulfur, and -2 for each oxygen atom.
Minus one for hydroxyl ( -OH) groups, minus two for oxo ( =O) groups.
There are many for S. Those are 0,2,4,6. some times they are minus.
In the compound Al2O3 oxygen is oxidized to minus 2. You will note that two aluminum times plus 3 is 6, and 3 oxygen times minus 2 is minus 6; thus the combination of aluminum and oxygen yields an electrically neutral molecule, since 6 - 6 = 0.
Pottasium got plus one. Iodine got minus one.
Silver has plus one.Chlorine has minus one.
The oxidation number of N in NO2 is +4. Each oxygen atom in NO2 has an oxidation state of -2, so the oxidation state of nitrogen can be calculated as follows: 2*(-2) + x = 0, where x is the oxidation state of N. Solving for x gives us x = +4.
The value of everything that individual owns - minus everything that an individual owes.
The oxidation number of chromium in CrBr2 is +2. This is because bromine typically has an oxidation number of -1 and there are two bromine atoms in CrBr2, leading to a total oxidation number of -2. The oxidation number of chromium must therefore be +2 to balance the charges.
In K₂CrO₄, the oxidation number of potassium (K) is +1, and the oxidation number of oxygen (O) is -2. Since the compound is neutral, the oxidation number of chromium (Cr) can be calculated as follows: 2(+1) + Cr + 4(-2) = 0. Solving for chromium, the oxidation number of chromium in K₂CrO₄ is +6.