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What is the oxidation number of O in the compound Na2SO4?
The oxidation number of oxygen (O) in most compounds, including sulfate (SO4), is typically -2. In Na2SO4, sodium (Na) has an oxidation number of +1. To calculate the oxidation number of oxygen in the compound, you would use the equation: 2(oxidation number of Na) + oxidation number of S + 4(oxidation number of O) = 0. By plugging in the known values, you can solve for the oxidation number of oxygen in Na2SO4.
What is the oxidation state of na2so4?
In Na2SO4, the oxidation state of sodium (Na) is +1, the oxidation state of sulfur (S) is +6, and the oxidation state of oxygen (O) is -2. To calculate the oxidation state of the whole compound, you can use the rule that the sum of the oxidation states in a neutral compound is zero, so in this case it would be +1*2 + (-2)*4 = 0.
What is the oxidation number of S in the compound Na2 SO4?
The oxidation number of S in Na2SO4 is +6. This is because the oxidation number of Na is +1 and of O is -2, and the overall charge of the compound is zero. Therefore, 2(+1) + x + 4(-2) = 0, where x is the oxidation number of S, which simplifies to x = +6.
What is the oxidation number of S in Li2SO4?
The oxidation number of sulfur (S) in Li2SO4 is +6. This is because lithium (Li) has an oxidation number of +1 and oxygen (O) has an oxidation number of -2, which allows us to calculate the oxidation number of sulfur.
Which element undergoes Oxidation in k2cro4 na2so3 hcl-kcl na2so4 crcl3 h2o?
Chromium undergoes oxidation in the given chemical equation. In this reaction, chromium changes from a +6 oxidation state to a +3 oxidation state, indicating that it has lost electrons and undergone oxidation.
What is the oxidation number of O in the compound Na2SO4?
The oxidation number of oxygen (O) in most compounds, including sulfate (SO4), is typically -2. In Na2SO4, sodium (Na) has an oxidation number of +1. To calculate the oxidation number of oxygen in the compound, you would use the equation: 2(oxidation number of Na) + oxidation number of S + 4(oxidation number of O) = 0. By plugging in the known values, you can solve for the oxidation number of oxygen in Na2SO4.
What is the oxidation state of na2so4?
In Na2SO4, the oxidation state of sodium (Na) is +1, the oxidation state of sulfur (S) is +6, and the oxidation state of oxygen (O) is -2. To calculate the oxidation state of the whole compound, you can use the rule that the sum of the oxidation states in a neutral compound is zero, so in this case it would be +1*2 + (-2)*4 = 0.
What is the oxidation number of S in the compound Na2 SO4?
The oxidation number of S in Na2SO4 is +6. This is because the oxidation number of Na is +1 and of O is -2, and the overall charge of the compound is zero. Therefore, 2(+1) + x + 4(-2) = 0, where x is the oxidation number of S, which simplifies to x = +6.
What is the oxidation number of S in Li2SO4?
The oxidation number of sulfur (S) in Li2SO4 is +6. This is because lithium (Li) has an oxidation number of +1 and oxygen (O) has an oxidation number of -2, which allows us to calculate the oxidation number of sulfur.
Which element undergoes Oxidation in k2cro4 na2so3 hcl-kcl na2so4 crcl3 h2o?
Chromium undergoes oxidation in the given chemical equation. In this reaction, chromium changes from a +6 oxidation state to a +3 oxidation state, indicating that it has lost electrons and undergone oxidation.
In CaSO4 the oxidation number of Ca is that of S is and that ofO is?
In CaSO4, the oxidation number of Ca is +2, the oxidation number of S is +6, and the oxidation number of O is -2.
What is the oxidation number for Na2SO3?
The oxidation number of Na in Na2SO3 is +1, the oxidation number for S in SO3 is +4, and the oxidation number for O in SO3 is -2.
What is the oxidation number for s2cl2?
The oxidation number of S in S2Cl2 is +1. Each Cl atom has an oxidation number of -1, and since the molecule is neutral, the overall oxidation numbers of S must balance out to zero. Thus, the oxidation number of S in this compound is +1.
Change in oxidation number in S2O82 TO SO42?
In S2O82-, each S atom has an oxidation number of +5. In SO42-, the oxidation number of S is also +5. There is no change in oxidation number for sulfur when transitioning from S2O82- to SO42-.
What is the oxidation number of NCS?
The oxidation number of NCS is -1. N has an oxidation number of -3, while S has an oxidation number of +6 in the NCS molecule.
What is the oxidation number for SOCl2?
In SOCl2, the oxidation numbers are as follows: Sulfur (S) has an oxidation number of +4 Oxygen (O) has an oxidation number of -2 Chlorine (Cl) has an oxidation number of -1
What is the oxidation number of H2SO4?
+1 for H +6 for S -2 for each O
