What is the oxidation number of carbon Cl4?

Answer 1

Assuming you mean Cl, with a lowercase L, which is chlorine:

As with all elements chlorine has an oxidation number of 0 in it's elemental form. In most of it's compounds its oxidation state is -1, but it can also exist in all oxidation states from -1 to +7 except for +2 and +6.

Answer 2

The oxidation number of a carbon tetrachloride molecule is 0. Chlorine, being more electronegative than carbon: each atom has -1 oxidation number. The oxidation number of carbon of +4 (four covalent bonds with four chlorine atoms).

Answer 3

Since HClO4 is neutral (has no net charge), you can calculate the oxidation number of Cl to be 7+. This is because each oxygen (O) is 2- and there are 4 of them for a total of 8-. The hydrogen (H) is 1+, so in order to balance the -8 of the oxygens, Cl would have to be 7+.

Answer 4

The oxidation number of Carbon in CI4 would be 4. "I" would equal -1. -1 times 4 = -4 -4 + what = 0 -4 + (+4) = 0

Answer 5

-1 for each iodine, +4 for carbon

Answer 6

-4