MoS2.
-2 for each S, +4 for Mo
MoS2. -2 for each S, +4 for Mo
The oxidation number of oxygen is typically -2, so for the whole MoO4^2- ion (which has a charge of -2), the total oxidation number must sum up to -2. This means that the oxidation number of molybdenum (Mo) in MoO4^2- would be +6.
The oxidation number of oxygen is typically -2. Since there are four oxygen atoms in MoO4-2 and the overall charge is -2, the oxidation number of molybdenum (Mo) is calculated to be +6 to balance the negative charge.
The oxidation number of molybdenum (Mo) in MoO4^2- is +6. This is because the overall charge of the compound is -2, and each oxygen atom has an oxidation number of -2. By setting up an equation (x + 4(-2) = -2), we find that x = +6.
The oxidation number of molybdenum (Mo) in the MoO4^2- ion is +6. This is because oxygen typically has an oxidation number of -2, and there are four oxygen atoms in the persulfate ion (O4^2-), making the total charge -8. For the overall ion to have a charge of -2, molybdenum must have an oxidation number of +6 to balance the charges.
MoS2. -2 for each S, +4 for Mo
The oxidation number of oxygen is typically -2, so for the whole MoO4^2- ion (which has a charge of -2), the total oxidation number must sum up to -2. This means that the oxidation number of molybdenum (Mo) in MoO4^2- would be +6.
The oxidation number of oxygen is typically -2. Since there are four oxygen atoms in MoO4-2 and the overall charge is -2, the oxidation number of molybdenum (Mo) is calculated to be +6 to balance the negative charge.
Roland I. E. Nwaogu has written: 'Molybdenum disulphide-filled thermosetting plastics'
The oxidation number of molybdenum (Mo) in MoO4^2- is +6. This is because the overall charge of the compound is -2, and each oxygen atom has an oxidation number of -2. By setting up an equation (x + 4(-2) = -2), we find that x = +6.
The oxidation number of molybdenum (Mo) in the MoO4^2- ion is +6. This is because oxygen typically has an oxidation number of -2, and there are four oxygen atoms in the persulfate ion (O4^2-), making the total charge -8. For the overall ion to have a charge of -2, molybdenum must have an oxidation number of +6 to balance the charges.
If you mean MoO4 the oxidation number of Mo is 8 and the compound would be called Mo(VIII) oxide. This compound does not exist, it is theoretical- teachers and examiners often use such nonexistent compounds as teaching aids- why I don't know- i think it is misleading as there are plenty of real compounds about.
In NaMoO3, sodium (Na) has an oxidation number of +1, oxygen (O) has an oxidation number of -2, and the overall charge of the compound is 0. Since there is only one Mo atom in the compound, the oxidation number of molybdenum (Mo) can be calculated to be +6 using the formula: (+1) + x + 3(-2) = 0 where x is the oxidation number of Mo.
MoPO4 is the formula for Molybdenum Phosphate with the Mo in oxidation state III. Mo can have multiple oxidation states. H3PMo12O40 is phosphomolybdic acid - see more information on this species at the related link.
In FeSO4, the oxidation number of Fe is +2, and the oxidation number of oxygen is -2. To find the oxidation number of S, we can set up an equation: 2(-2) + x + 4(-2) = 0 (overall charge of the compound is zero). Solving this equation gives the oxidation number of S as +6.
The atomic number of molybdenum (Mo) is 42. See the Web Links to the left of this answer for a periodic table with more information about this element!
Most molybdenum atoms have 54 neutrons. The atomic number (number of protons) of molybdenum is 42, and its weight (number of protons and neutrons) is around 96. 96 - 42 = 54.