S = +4 oxidation state
O = -2 oxidation state
Sulphar has +4 oxidation state.Oxygen has -2 oxidation state.
In an oxidation reaction there is addition of oxygen molecules or removal of hydrogen molecules from a compound and loss of electrons from an atom / ion . example - S + O2 = SO2
Asbestos is avoided because his carcinogenic properties.
(Inlet SO2-Exit SO2)X100 ----------------------------- Inlet-(1.5xinletXExit)/100
No, there is no change in any oxidation states.
Sulphar has +4 oxidation state.Oxygen has -2 oxidation state.
Oxidation state of O is -2.Oxidation state of S is +4.
+6, because the oxidation number of oxygen is -2x3=-6
-2 for each O +4 for S
The oxidation number is 0 in elemental form. It can have other oxidation numbers as -2, +4 and +6 in its compounds such as H2S, SO2 and SO3 respectively.-2, 0, 2, 4 and 6 oxidation states
Sulfur can have a wide range of oxidation in its compounds -2 in H2S 0 in elementary sulfur (S8) +4 in SO2 +6 in SO3
-2 for each O +4 for S
In an oxidation reaction there is addition of oxygen molecules or removal of hydrogen molecules from a compound and loss of electrons from an atom / ion . example - S + O2 = SO2
Things are complicated if we use the term valency. It is better to use the term Oxidation state or Oxidation Number. In SO2, the oxidation state of sulphur is +4 and In SO3, the oxidation state of sulphur is +6.
Since the total molecule must have zero net oxidation state and there are two oxygen atoms but only one sulfur atom, the sulfur must have oxidation state +4.
Asbestos is avoided because his carcinogenic properties.
Pyrite (fools gold) reacts with Oxygen to make Hematite (Fe2O3) and Sulpher dioxide (SO2) The reaction is oxidation of pyrite. 2FeS2 + 3.5O2 - - Fe2O3 + 2SO2