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C = +2 oxidation state O = -2 oxidation state
K = +1 oxidation state Cl = +3 oxidation state O = -2 oxidation state
O = -2 oxidation state H = +1 oxidation state
S = +4 oxidation state O = -2 oxidation state
The oxidation state is +3.
+4 oxidation state
+4 oxidation state
It depends on what form it is in. It can be in the 4+ oxidation state, 4- oxidation state and every oxidation state in between.
Co = +2 oxidation C = +4 oxidation O = -2 oxidation
C = +2 oxidation state O = -2 oxidation state
Zinc is in oxidation state +2 and oxygen in oxidation state -2. Zinc Oxide itself has not net charge/oxidation state.
Here O S of C is -4As,let us take O S of C as xSo, O S of H is +1In CH4 as it is stable so the eq. isx+4(+1)=0or, x = - 4
There are NO carbon (C) atoms in potassium nitrate (KNO3). B.t.w. atoms always have an oxidation state to be zero.
Fermentation is not considered as an oxydation reaction. ------------------------------------------------------------------ It may not usually be considered as such, but the oxidation state of C in sugar is zero, and the oxidation state of C in ethanol is -2. Any change in oxidation state can be treated as a redox process. Loss of electrons (or an increase of oxidation state) is oxidation, gain of electrons (or a decrease of oxidation state) is reduction. The carbon that ends up in the ethanol has decreased its oxidation state from 0 to -2 so those atoms have undergone reduction. Reduction cannot exist without a subsequent oxidation, so something else has undergone oxidation. The fermentation process also makes carbon dioxide. The C in those molecules has an oxidation state of +4, so those atoms of carbon have been oxidized. So the answer is --- both.
-2 oxidation state
K = +1 oxidation state Cl = +3 oxidation state O = -2 oxidation state
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