Simply remember OIL RIG. Oxidation Is Loss (of electron) and Reduction Is Gain (of electron). In the case of MnO4-(aq) + 8H+(aq) + 5e- --> Mn2+(aq) + 4H2O(l) H is the oxidizing agent, because it causes Mn to be oxidized to Mn2+.
K = +1 oxidation state Cl = +3 oxidation state O = -2 oxidation state
O = -2 oxidation state H = +1 oxidation state
S = +4 oxidation state O = -2 oxidation state
The oxidation state is +3.
The oxidation number of Mn in the molecule Mn2 would be 0.
manganese is a 3d element. +2 is the oxidation number in this ion.
O.S. of Mn = +3 O.S. of O = -2 O.N. of cpd = 0
Reduction Half-Reaction: MnO4-(aq) → Mn2+(aq) Oxidation Half-Reaction: Cl-(aq) → Cl2(g)
Simply remember OIL RIG. Oxidation Is Loss (of electron) and Reduction Is Gain (of electron). In the case of MnO4-(aq) + 8H+(aq) + 5e- --> Mn2+(aq) + 4H2O(l) H is the oxidizing agent, because it causes Mn to be oxidized to Mn2+.
In this case the roman numerals indicate the oxidation state of the cation portion of the polyatomic ion: [Fe(II)O2]2- as opposed to [Fe(III)O2]1- Mn(II)=Mn2+ Mn(VII)=Mn7+
-2 oxidation state
K = +1 oxidation state Cl = +3 oxidation state O = -2 oxidation state
Fe = +3 oxidation state Cl = -1 oxidation state
O = -2 oxidation state H = +1 oxidation state
Mg = +2 oxidation state P = +5 oxidation state O = -2 oxidation state
It depends on what form it is in. It can be in the 4+ oxidation state, 4- oxidation state and every oxidation state in between.