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The principal oxidation state of NA in NA2O2 and K in KO2 is +1
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What is the oxidation number of Na in Na2O2?
+1 for each Na -1 for oxygen (as it is peroxide)
What is the oxidation number of Na2O2?
+1 for each Na -1 for each O (peroxide)
What is the percent yield for the reaction of 6.92 g of K and 4.28 g of O2 if 7.36 g of KO2 is recovered in the laboratory?
First you need to find the theoretical yield for the reaction:2Na + O2 ---> Na2O2(1) find the theoretical yield of 3.74 g of Na, i.e. if all of the Na is reacted3.74 g Na *(1 mol Na/22.99 g Na)*(1 mol Na2O2 formed/2 mol Na reacted)*(77.98 g Na2O2/1 mol Na2O2) = 6.34 g Na2O2(2) % yield = (actual yield / theoretical yield)*(100%)% yield = (5.34 g / 6.34 g) *(100%) = 84.2% yield
What type of reaction occurs between Na plus O2?
4 Na + O2 → 2 Na2O2 Na + O2 → Na2O2
What is the oxidation state of NaBrO3?
In NaBrO3 the oxidation state of sodium (Na) is 1+, the oxidation state of bromine is 5+ and the oxidation state of each oxygen atom is 2-
What is the oxidation number of Na in Na2O2?
+1 for each Na -1 for oxygen (as it is peroxide)
What is the oxidation number of Na2O2?
+1 for each Na -1 for each O (peroxide)
What is the percent yield for the reaction of 6.92 g of K and 4.28 g of O2 if 7.36 g of KO2 is recovered in the laboratory?
First you need to find the theoretical yield for the reaction:2Na + O2 ---> Na2O2(1) find the theoretical yield of 3.74 g of Na, i.e. if all of the Na is reacted3.74 g Na *(1 mol Na/22.99 g Na)*(1 mol Na2O2 formed/2 mol Na reacted)*(77.98 g Na2O2/1 mol Na2O2) = 6.34 g Na2O2(2) % yield = (actual yield / theoretical yield)*(100%)% yield = (5.34 g / 6.34 g) *(100%) = 84.2% yield
What type of reaction occurs between Na plus O2?
4 Na + O2 → 2 Na2O2 Na + O2 → Na2O2
What is chemical symbol for sodium peroxide?
Na2O2, or Na-O-O-Na.
What is the oxidation state of NaBrO3?
In NaBrO3 the oxidation state of sodium (Na) is 1+, the oxidation state of bromine is 5+ and the oxidation state of each oxygen atom is 2-
What is the oxidation state of na2so4?
This is a neutral compound. Na shows the +1 OXIDATION NUMBER.
What is the oxidation state of Sodium Nitrate?
Sodium Oxide, or NaOH, has no oxidation state. It has a charge, which is zero. The elements that make up NaOH, however, do have oxidation states. The oxidation state of sodium (Na) is +1, and it will forever be +1 because it is impossible for it to be anything else, no matter what situation. The same applies for Hydrogen. Oxygen has an oxidation state of -2, and almost always will have an oxidation state of -2. There is one notable exception: H2O2. In this case, since the total charge of the compound is neutral and the oxidation state of Hydrogen must be +1 and, seeing as there are two hydrogens, bringing the overall charge up to 2, the oxidation state of oxygen must be -1. If it was -2, then the molecule would have an overall charge of -2.
What is the oxidation number of solid sodium metal Na?
zero bcoz the oxidation no of element in free state is zero
What is the chemical formula for Na plus and O2 and minus?
The chemical equation is:6 Na + 2 O2 = 2 Na2O + Na2O2
How does the oxidation state of Na change in the following reaction Li NaOH LiOH Na?
It goes from +1 to 0
How does the oxidation state of Na change in the following reaction?
It goes from +1 to 0.
