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First you need to find the theoretical yield for the reaction:

2Na + O2 ---> Na2O2

(1) find the theoretical yield of 3.74 g of Na, i.e. if all of the Na is reacted

3.74 g Na *(1 mol Na/22.99 g Na)*(1 mol Na2O2 formed/2 mol Na reacted)*(77.98 g Na2O2/1 mol Na2O2) = 6.34 g Na2O2

(2) % yield = (actual yield / theoretical yield)*(100%)

% yield = (5.34 g / 6.34 g) *(100%) = 84.2% yield

More answers

This percent yield is 58.5 %.

Q: What is the percent yield for the reaction of 6.92 g of K and 4.28 g of O2 if 7.36 g of KO2 is recovered in the laboratory?

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the percent yield be the actual yield (392) divided by the theoretical yield (i calculated 450). 392/450 equals .87 multiply by 100 and the percent yield is 87%.

98.2 % 98.2 %

The percent yield in this case is 89,25 %.

the amount of product obtained over the amount possible multiplied by 100

8.67 x 100 / 11.22 = 77.27...%

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88.8%

The percent yield of a reaction measures the efficiency of a reaction. The relationship of the actual yield to the theoretical yield is used to determine this.

Yield (also called as actual yield) is the amount of a product (aspirin) obtained by an experiment in a chemical reaction in a laboratory.

the percent yield be the actual yield (392) divided by the theoretical yield (i calculated 450). 392/450 equals .87 multiply by 100 and the percent yield is 87%.

98.2 % 98.2 %

percent yield

Percent Yield

(Actual yield / Theoretical yield) x 100%

The percent yield in this case is 89,25 %.

Percentage yield = (Actual yield / Theoretical yield) x 100% The percentage yield for a reaction is a value between 0 to 100 percent.

the amount of product obtained over the amount possible multiplied by 100