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# What is the percent yield for the reaction of 6.92 g of K and 4.28 g of O2 if 7.36 g of KO2 is recovered in the laboratory?

Updated: 8/11/2023

Wiki User

11y ago

First you need to find the theoretical yield for the reaction:

2Na + O2 ---> Na2O2

(1) find the theoretical yield of 3.74 g of Na, i.e. if all of the Na is reacted

3.74 g Na *(1 mol Na/22.99 g Na)*(1 mol Na2O2 formed/2 mol Na reacted)*(77.98 g Na2O2/1 mol Na2O2) = 6.34 g Na2O2

(2) % yield = (actual yield / theoretical yield)*(100%)

% yield = (5.34 g / 6.34 g) *(100%) = 84.2% yield

Wiki User

12y ago

Wiki User

11y ago

This percent yield is 58.5 %.

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Q: What is the percent yield for the reaction of 6.92 g of K and 4.28 g of O2 if 7.36 g of KO2 is recovered in the laboratory?
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