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What is the percent yield for the reaction of 6.92 g of K and 4.28 g of O2 if 7.36 g of KO2 is recovered in the laboratory?
Wiki User
∙ 11y ago
First you need to find the theoretical yield for the reaction:
2Na + O2 ---> Na2O2
(1) find the theoretical yield of 3.74 g of Na, i.e. if all of the Na is reacted
3.74 g Na *(1 mol Na/22.99 g Na)*(1 mol Na2O2 formed/2 mol Na reacted)*(77.98 g Na2O2/1 mol Na2O2) = 6.34 g Na2O2
(2) % yield = (actual yield / theoretical yield)*(100%)
% yield = (5.34 g / 6.34 g) *(100%) = 84.2% yield
Wiki User
∙ 12y ago
Wiki User
∙ 11y agoThis percent yield is 58.5 %.
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When 320g octane C8H18 is burned in oxygen 392g of water is recovered what is the percent yield of the experiment?
the percent yield be the actual yield (392) divided by the theoretical yield (i calculated 450). 392/450 equals .87 multiply by 100 and the percent yield is 87%.
The actual yield of the given reaction is 14.4what is your percent yield?
98.2 % 98.2 %
What is the percent yield for iron if the reaction of 65.0 g of iron(III) oxide produces 42.0g of iron?
The percent yield in this case is 89,25 %.
How do you obtain percent yield of a reaction?
the amount of product obtained over the amount possible multiplied by 100
What would be the percent yield of the reaction be if the theoretical yield is 11.22 g but the actual yield was 8.67 g?
In this case the yield is 77,27 %.
Consider a reaction between 5.39 moles of ironIII oxide and excess aluminum in the thermite reaction If 526 g of liquid iron were recovered after the reaction was complete what was the percent yield o?
87.4%
Consider a reaction between 8.63 moles of ironIII oxide and excess aluminum in the thermite reaction If 856 g of liquid iron were recovered after the reaction was complete what was the percent yield o?
88.8%
What relationship s used to determine the percent yield of a chemical reaction?
The percent yield of a reaction measures the efficiency of a reaction. The relationship of the actual yield to the theoretical yield is used to determine this.
What is yield of aspirin?
Yield (also called as actual yield) is the amount of a product (aspirin) obtained by an experiment in a chemical reaction in a laboratory.
When 320g octane C8H18 is burned in oxygen 392g of water is recovered what is the percent yield of the experiment?
the percent yield be the actual yield (392) divided by the theoretical yield (i calculated 450). 392/450 equals .87 multiply by 100 and the percent yield is 87%.
The actual yield of the given reaction is 14.4what is your percent yield?
98.2 % 98.2 %
Dividing the actual yield by the theoretical yield and multiplying by 100 indicates reaction efficiency and is known as the?
percent yield
Dividing the actual yield by the theoretical yield and multiplying by 100 indicates reaction efficiency and is known as there?
Percent Yield
The percent yield of the given reaction is 70.4 C2H5OHHBrC2H5BrH2O What is the actual yield if 80.0g of C2H5OH was used for the reaction This is what I came up with. 70.480.010056.32 help?
(Actual yield / Theoretical yield) x 100%
What is the percent yield for iron if the reaction of 65.0 g of iron(III) oxide produces 42.0g of iron?
The percent yield in this case is 89,25 %.
What is the Formula for percentage yield?
Percentage yield = (Actual yield / Theoretical yield) x 100% The percentage yield for a reaction is a value between 0 to 100 percent.
How do you obtain percent yield of a reaction?
the amount of product obtained over the amount possible multiplied by 100
