N has +3 state on it.Each H have -1 state.
Assuming you mean NH3 since there is no N3H ....The charge on NH3 is zero; it doesn't have an oxidation number. The oxidation number of N in NH3 is 3- The oxidation number of each H in NH3 is 1+
In NH3 the oxidation state of Nitrogen is -3. It has 3 extra electrons in three polar covalent bonds, 'donated' from three bonded hydrogen atoms. Hydrogen has an oxidation state of +1 in this compound.
nitrogen is -3 H is plus 1
This is an oxidation reaction of N from -3 (in NH3) to +2 (in NO) oxidation value. 4 NH3 + 5 O2 --> 6 H2O + 4 NO
N has +3 state on it.Each H have -1 state.
Assuming you mean NH3 since there is no N3H ....The charge on NH3 is zero; it doesn't have an oxidation number. The oxidation number of N in NH3 is 3- The oxidation number of each H in NH3 is 1+
In NH3 the oxidation state of Nitrogen is -3. It has 3 extra electrons in three polar covalent bonds, 'donated' from three bonded hydrogen atoms. Hydrogen has an oxidation state of +1 in this compound.
Hydrogen has an oxidation state of +1 whenever it interacts with a more electronegative element to form a compound (NH3) or whenever it forms an ionic-bonded acid (HClO4) or functions as a cation (NaHCO3). Hydrogen has an oxidation state of 0 in its elemental form. (H2) Hydrogen has an oxidation state of -1 whenever it forms and ionic salt as an anion. (LiH).
nitrogen is -3 H is plus 1
This is an oxidation reaction of N from -3 (in NH3) to +2 (in NO) oxidation value. 4 NH3 + 5 O2 --> 6 H2O + 4 NO
-2 oxidation state
K = +1 oxidation state Cl = +3 oxidation state O = -2 oxidation state
Fe = +3 oxidation state Cl = -1 oxidation state
O = -2 oxidation state H = +1 oxidation state
Mg = +2 oxidation state P = +5 oxidation state O = -2 oxidation state
It depends on what form it is in. It can be in the 4+ oxidation state, 4- oxidation state and every oxidation state in between.