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111.72
The moLaRity of this solution ie 2 mol/L or 2M KI (it is a 'two molair potassium iodide' solution)
1x10-2M
2m
You cannot answer this without also knowing the VOLUME of the 2 M solution. For example, if you have 1 liter of 2 M NaOH, the the mass contained in that bottle will be 1L x 2 mol/L x 40 g/mol = 80 g.If, however, you have 2 liter, then the mass of NaOH contained in that bottle will be 160 g. And so on.
111.72
Just dissolve 8g solid NaOH in 100 mls. distilled water.
The moLaRity of this solution ie 2 mol/L or 2M KI (it is a 'two molair potassium iodide' solution)
2M NaCl is a equivalent to a solution with 116,88 g NaCl in 1 L water.
Concentrated bases (more than 2M/L) as sodium hydroxide for example.
Concentrated bases (more than 2M/L) as sodium hydroxide for example.
Concentrated bases (more than 2M/L) as sodium hydroxide for example.
You have to evaporate (by open boiling) 45 mL of the 75 mL 2M NaCl solution thus reducing the volume to 30 mL 5M NaCl.
2m
1x10-2M
2 moles of HCl for every liter of solution.
Without an equality sign it has no solutions but as an algebraic expression it can be simplified depending on the plus or minus values of 8m and 2m