Molarity is the concentration of a solution, defined as moles per unit volume.
Where,
Molarity = moles / volume
In this case the molarity of the HCl solution is 0.03 M
The pH of this is calculated by the equation below
pH = - log [H+]
Where [H+] is the concentration of hydrogen ions/ protons present in the solution.
As HCl only contains one hydrogen ion per molecule then the concentation of [H+] is 0.03 M
Then the equation can be calculated (the minus sign is very important!)
pH = - log 0.03
pH = 1.52
To summarise,
Molarity of 0.03 M HCl solution is 0.03 M
pH of 0.03 M HCl solution is 1.52
pOH=-log(3.0M)
pOH=-0.4771212547
pH=14-pOH
pH=14-(-0.477121254700
pH=14.5
pH of 3.00 M of HCl
0.04 M KOH produces an OH- concentration of 0.04 M. Thus, the pOH is -log 0.04 = 1.4 and the pH will be 14 - 1.4 = 12.6
-log(1.0 X 10^-4 M KOH) = 4 14 - 4 = 10 pH KOH ----------------
9
9
Molarity = moles of solute/Liters of solution get moles KOH 6.31 grams KOH (1 mole KOH/56.108 grams) = 0.11246 moles KOH 0.250 M KOH = 0.11246 moles KOH/XL 0.11246/0.250 = 0.4498 liters = 450 milliliters
0.04 M KOH produces an OH- concentration of 0.04 M. Thus, the pOH is -log 0.04 = 1.4 and the pH will be 14 - 1.4 = 12.6
-log(1.0 X 10^-4 M KOH) = 4 14 - 4 = 10 pH KOH ----------------
9
9
-log(3.5 X 10^-4 M) = 3.4559 14 - 3.4559 = 10.5 pH
Molarity = moles of solute/Liters of solution get moles KOH 6.31 grams KOH (1 mole KOH/56.108 grams) = 0.11246 moles KOH 0.250 M KOH = 0.11246 moles KOH/XL 0.11246/0.250 = 0.4498 liters = 450 milliliters
10.332
[OH-] = 1x10^-3 M[H+][OH-] = 1x10^-14[H+] = 1x10^-14/1x10^-3 = 1x10^-11pH = -log 1x10^-11 = 11Done another way:pOH = -log [OH-] = -log 1x10^-3 = 3pH + pOH = 14pH = 14 - 3 = 11
30 mL of HCl
The pH of water increase.
concentrated solution of NaOH and KOH have the pH value about 13.
I assume you mean 7.25 M KOH, but the process is the same anyway.Molarity = moles of solute/Liters of solution ( 400 ml = 0.4 Liters )7.25 M KOH = X moles KOH/0.4 Liters= 2.9 moles KOH (56.108 grams/1 mole KOH)= 163 grams potassium hydroxide needed===============================