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[OH-] = 1x10^-3 M
[H+][OH-] = 1x10^-14
[H+] = 1x10^-14/1x10^-3 = 1x10^-11
pH = -log 1x10^-11 = 11
Done another way:
pOH = -log [OH-] = -log 1x10^-3 = 3
pH + pOH = 14
pH = 14 - 3 = 11

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