You think probable to potassium chloride.
KCl is a salt having Ph 7, it is highly ionizable.yet a small leakage of ions from the reference electrode is needed, forming a conducting bridge to the glass electrode. A pH meter must thus not be used in moving liquids of low conductivity. Sushant kumar
No, the saturated calomel reference electrode is not suitable for use in strong alkaline solutions like 2-5 N KOH. The high pH environment can damage the electrode and affect its performance. It is better to use a reference electrode designed specifically for use in alkaline media, such as a silver/silver chloride electrode.
To prepare a 30% methanolic KOH solution, you would mix 30g of KOH with enough methanol to make a total solution volume of 100mL. This would result in a solution where 30% of the total weight comes from KOH. Be cautious when handling KOH as it is a caustic substance and should be handled with appropriate precautions.
To find the molarity of the KOH solution, we need to know the concentration of the KOH solution in moles per liter. Without this information, we cannot calculate the molarity.
To dilute the 5M KOH solution to 3M, we can use the formula: M1V1 = M2V2, where M1 = initial molarity, V1 = initial volume, M2 = final molarity, and V2 = final volume. Plugging in the values, we get: (5M)(0.5L) = (3M)(V2). Solving for V2 gives V2 = 0.5 * 5 / 3 = 0.833 L. So, 0.833 liters of 3M KOH solution can be prepared by diluting 0.5L of 5M KOH solution.
KCl is a salt having Ph 7, it is highly ionizable.yet a small leakage of ions from the reference electrode is needed, forming a conducting bridge to the glass electrode. A pH meter must thus not be used in moving liquids of low conductivity. Sushant kumar
No, the saturated calomel reference electrode is not suitable for use in strong alkaline solutions like 2-5 N KOH. The high pH environment can damage the electrode and affect its performance. It is better to use a reference electrode designed specifically for use in alkaline media, such as a silver/silver chloride electrode.
because KOH is hygroscopic
The concentration is 1 mol/L or 5,611 g KOH/100 mL solution.
The answer is 12,831 g KOH.
To prepare a 30% methanolic KOH solution, you would mix 30g of KOH with enough methanol to make a total solution volume of 100mL. This would result in a solution where 30% of the total weight comes from KOH. Be cautious when handling KOH as it is a caustic substance and should be handled with appropriate precautions.
To find the molarity of the KOH solution, we need to know the concentration of the KOH solution in moles per liter. Without this information, we cannot calculate the molarity.
A solution that is refered to as a percentage of something (like potassium hydroxide, KOH) refers to the mass of the solute compared to the total solution, so a 5% KOH solution would be 5g KOH + 95g H2O, and the 5g KOH would be 5% of the 100g total of the solution.
To dilute the 5M KOH solution to 3M, we can use the formula: M1V1 = M2V2, where M1 = initial molarity, V1 = initial volume, M2 = final molarity, and V2 = final volume. Plugging in the values, we get: (5M)(0.5L) = (3M)(V2). Solving for V2 gives V2 = 0.5 * 5 / 3 = 0.833 L. So, 0.833 liters of 3M KOH solution can be prepared by diluting 0.5L of 5M KOH solution.
The reaction between HBr and KOH is a 1:1 ratio. This means that the moles of HBr present in the solution will be equal to the moles of KOH used in the neutralization reaction. Using this information and the volume and concentration of KOH used, you can calculate the concentration of the HBr solution.
The answer is10,436 g.
Yes, KOH (potassium hydroxide) in water exists as an aqueous solution.