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Why the pH meter is always kept in saturated KOH solution?
KCl is a salt having Ph 7, it is highly ionizable.yet a small leakage of ions from the reference electrode is needed, forming a conducting bridge to the glass electrode. A pH meter must thus not be used in moving liquids of low conductivity. Sushant kumar
Can the saturated calomel reference electrode be used in strong alkaline media such as 2-5 N KOH solution?
No, the saturated calomel reference electrode is not suitable for use in strong alkaline solutions like 2-5 N KOH. The high pH environment can damage the electrode and affect its performance. It is better to use a reference electrode designed specifically for use in alkaline media, such as a silver/silver chloride electrode.
How do you prepare 30 percent of methanolic KOH solution?
To prepare a 30% methanolic KOH solution, you would mix 30g of KOH with enough methanol to make a total solution volume of 100mL. This would result in a solution where 30% of the total weight comes from KOH. Be cautious when handling KOH as it is a caustic substance and should be handled with appropriate precautions.
you have 500 ml of a 1.5 m hcl solution (acid). if there is 250 ml of koh solution present (base). what will be the molarity of the koh (base)?
To find the molarity of the KOH solution, we need to know the concentration of the KOH solution in moles per liter. Without this information, we cannot calculate the molarity.
What volume of a 3m koh solution can be prepared by diluting 0.5 l of a 5m koh solution?
To dilute the 5M KOH solution to 3M, we can use the formula: M1V1 = M2V2, where M1 = initial molarity, V1 = initial volume, M2 = final molarity, and V2 = final volume. Plugging in the values, we get: (5M)(0.5L) = (3M)(V2). Solving for V2 gives V2 = 0.5 * 5 / 3 = 0.833 L. So, 0.833 liters of 3M KOH solution can be prepared by diluting 0.5L of 5M KOH solution.
Why the pH meter is always kept in saturated KOH solution?
KCl is a salt having Ph 7, it is highly ionizable.yet a small leakage of ions from the reference electrode is needed, forming a conducting bridge to the glass electrode. A pH meter must thus not be used in moving liquids of low conductivity. Sushant kumar
Can the saturated calomel reference electrode be used in strong alkaline media such as 2-5 N KOH solution?
No, the saturated calomel reference electrode is not suitable for use in strong alkaline solutions like 2-5 N KOH. The high pH environment can damage the electrode and affect its performance. It is better to use a reference electrode designed specifically for use in alkaline media, such as a silver/silver chloride electrode.
Why alcohol is required in koh solution?
because KOH is hygroscopic
What is the molarity of a solution when 50.0ml of a 4.00M KOH solution is diluted to 200ml. what is the percent concentration of KOH in this final solution. asume the density of 1.0gmole?
The concentration is 1 mol/L or 5,611 g KOH/100 mL solution.
How many grams of KOH are present in 31.5 mL of a 7.26M KOH solution?
The answer is 12,831 g KOH.
How do you prepare 30 percent of methanolic KOH solution?
To prepare a 30% methanolic KOH solution, you would mix 30g of KOH with enough methanol to make a total solution volume of 100mL. This would result in a solution where 30% of the total weight comes from KOH. Be cautious when handling KOH as it is a caustic substance and should be handled with appropriate precautions.
you have 500 ml of a 1.5 m hcl solution (acid). if there is 250 ml of koh solution present (base). what will be the molarity of the koh (base)?
To find the molarity of the KOH solution, we need to know the concentration of the KOH solution in moles per liter. Without this information, we cannot calculate the molarity.
How do you make 5 percent potassium hydroxide solution?
A solution that is refered to as a percentage of something (like potassium hydroxide, KOH) refers to the mass of the solute compared to the total solution, so a 5% KOH solution would be 5g KOH + 95g H2O, and the 5g KOH would be 5% of the 100g total of the solution.
What volume of a 3m koh solution can be prepared by diluting 0.5 l of a 5m koh solution?
To dilute the 5M KOH solution to 3M, we can use the formula: M1V1 = M2V2, where M1 = initial molarity, V1 = initial volume, M2 = final molarity, and V2 = final volume. Plugging in the values, we get: (5M)(0.5L) = (3M)(V2). Solving for V2 gives V2 = 0.5 * 5 / 3 = 0.833 L. So, 0.833 liters of 3M KOH solution can be prepared by diluting 0.5L of 5M KOH solution.
What is the concentration of an HBr solution if 12.0 mL of the solution is neutralized by 15.0 mL of a 0.25 M KOH solution?
The reaction between HBr and KOH is a 1:1 ratio. This means that the moles of HBr present in the solution will be equal to the moles of KOH used in the neutralization reaction. Using this information and the volume and concentration of KOH used, you can calculate the concentration of the HBr solution.
How many grams of KOH are in 37.5 mL of 4.96M KOH solution?
The answer is10,436 g.
What is the molarity of a KOH solution if 24.6 mL neutralizes 44.0 mL of a 0.211 M HCl?
To find the molarity of the KOH solution, we first need to determine the number of moles of HCl used in the reaction (n(HCl) = Molarity x Volume). Then, since KOH and HCl react in a 1:1 ratio, the number of moles of KOH will be the same. Finally, calculate the molarity of KOH using the moles of KOH and the volume of KOH solution used.
