The net ionic equation for RbCl(aq) + KOH(aq) is Rb+(aq) + OH-(aq) -> RbOH(s).
Overall ionic equation: K+(aq) +OH-(aq)+ H30+(aq) + Cl-(aq)------>2H20 (l) + K+(aq) + Cl-(aq) Net ionic Equation OH-(aq)+ H30+(aq) ------>2H20 (l)
The reaction is:3 KOH + Fe(NO3)3 = Fe(OH)3 + 3 KNO3
CH3COOH + KOH = CH3COOK + H2O
HNO3(aq) + KOH(aq) --> KNO3(aq) + H2O(l) Because HNO3 is a strong acid, when it combines with a strong base it will react. When you deal with a problem like this the positive ions, H+ and K+ switch places.
The net ionic equation for RbCl(aq) + KOH(aq) is Rb+(aq) + OH-(aq) -> RbOH(s).
Overall ionic equation: K+(aq) +OH-(aq)+ H30+(aq) + Cl-(aq)------>2H20 (l) + K+(aq) + Cl-(aq) Net ionic Equation OH-(aq)+ H30+(aq) ------>2H20 (l)
The reaction is:3 KOH + Fe(NO3)3 = Fe(OH)3 + 3 KNO3
CH3COOH + KOH = CH3COOK + H2O
HNO3(aq) + KOH(aq) --> KNO3(aq) + H2O(l) Because HNO3 is a strong acid, when it combines with a strong base it will react. When you deal with a problem like this the positive ions, H+ and K+ switch places.
When KOH (potassium hydroxide) aqueous neutralizes HCl (hydrochloric acid) aqueous, potassium chloride (KCl) and water (H2O) are produced. This reaction is a neutralization reaction where the acid and base react to form a salt and water.
The chemical equation for the neutralization reaction of potassium hydroxide (KOH) with nitric acid (HNO3) is: KOH + HNO3 → KNO3 + H2O This reaction produces potassium nitrate (KNO3) and water (H2O).
KOH(aq)+HC2H3O2(aq)---- H2O(l)+KC2H3O2(aq)
HNO3(aq) + KOH(aq) --> KNO3(aq) + H2O(l) Because HNO3 is a strong acid, when it combines with a strong base it will react. When you deal with a problem like this the positive ions, H+ and K+ switch places.
This is an acid + alkali = salt + Water reaction. Hydrochloric Acid + potassium hydroxide = potassium chloride and water. HCl(aq) + KOH(aq) = KCl(aq) + H2O(l)
H+(aq)+OH−(aq)→H2O(l)
They do not react, the Calcium cannot displace the Potassium as it is less reactive.