KOH (aq) + HCl (aq) = KCl (aq) + H20 so potassium chloride and water - KCl solution
KOH(aq) + HNO3(aq) = KNO3(aq) + H2O(l)
Overall ionic equation: K+(aq) +OH-(aq)+ H30+(aq) + Cl-(aq)------>2H20 (l) + K+(aq) + Cl-(aq) Net ionic Equation OH-(aq)+ H30+(aq) ------>2H20 (l)
K2SO4 and H2O
HCHO2 is methanoic acid and is normally written as HCOOH. When reacted with potassium hydroxide (KOH) , it produces potassium methanoate. and water/ HCOOH +KOH = HCOO^-K+ + H2O
KOH (aq) + HCl (aq) = KCl (aq) + H20 so potassium chloride and water - KCl solution
KOH(aq) + HNO3(aq) = KNO3(aq) + H2O(l)
Overall ionic equation: K+(aq) +OH-(aq)+ H30+(aq) + Cl-(aq)------>2H20 (l) + K+(aq) + Cl-(aq) Net ionic Equation OH-(aq)+ H30+(aq) ------>2H20 (l)
K2SO4 and H2O
KOH(aq) + NaCl(aq)
HCHO2 is methanoic acid and is normally written as HCOOH. When reacted with potassium hydroxide (KOH) , it produces potassium methanoate. and water/ HCOOH +KOH = HCOO^-K+ + H2O
The reaction is:3 KOH + Fe(NO3)3 = Fe(OH)3 + 3 KNO3
KOH(aq.)+HCl(aq.)-->H2O(l.)+KCL(aq.)
HNO3(aq) + KOH(aq) --> KNO3(aq) + H2O(l) Because HNO3 is a strong acid, when it combines with a strong base it will react. When you deal with a problem like this the positive ions, H+ and K+ switch places.
HNO3(aq) + KOH(aq) --> KNO3(aq) + H2O(l) Because HNO3 is a strong acid, when it combines with a strong base it will react. When you deal with a problem like this the positive ions, H+ and K+ switch places.
The molecular equation is 2KOH(aq) + CoBr2(aq) ==> 2KBr(aq) + Co(OH)2(s)The spectator ions are K^+ and Br^-
CH3COOH(aq) + KOH(aq) --->CH3COOK(aq) + H2O(l)You can obtain the CH3COOK by removal of the water.