because KOH is hygroscopic
The concentration is 1 mol/L or 5,611 g KOH/100 mL solution.
The answer is 12,831 g KOH.
To find the molarity (M) of the KOH solution, first calculate the number of moles of KOH. The molar mass of KOH is approximately 56.11 g/mol. Therefore, 28 g of KOH corresponds to about 0.498 moles (28 g ÷ 56.11 g/mol). Finally, the molarity is calculated as moles of solute per liter of solution: ( M = \frac{0.498 \text{ moles}}{2 \text{ L}} = 0.249 , M ). Thus, the molarity of the solution is approximately 0.25 M.
It's a solution... but solutions are mixtures.
Moles KOH = Molarity x Volume = 0.214 moles/liter x 0.0602 liters = 0.0129 moles KOH. Remember, 60.2 mL = 0.062L
The concentration is 1 mol/L or 5,611 g KOH/100 mL solution.
The answer is 12,831 g KOH.
To prepare a 30% methanolic KOH solution, you would mix 30g of KOH with enough methanol to make a total solution volume of 100mL. This would result in a solution where 30% of the total weight comes from KOH. Be cautious when handling KOH as it is a caustic substance and should be handled with appropriate precautions.
To find the molarity of the KOH solution, we need to know the concentration of the KOH solution in moles per liter. Without this information, we cannot calculate the molarity.
A solution that is refered to as a percentage of something (like potassium hydroxide, KOH) refers to the mass of the solute compared to the total solution, so a 5% KOH solution would be 5g KOH + 95g H2O, and the 5g KOH would be 5% of the 100g total of the solution.
To dilute the 5M KOH solution to 3M, we can use the formula: M1V1 = M2V2, where M1 = initial molarity, V1 = initial volume, M2 = final molarity, and V2 = final volume. Plugging in the values, we get: (5M)(0.5L) = (3M)(V2). Solving for V2 gives V2 = 0.5 * 5 / 3 = 0.833 L. So, 0.833 liters of 3M KOH solution can be prepared by diluting 0.5L of 5M KOH solution.
To prepare a 1N alcoholic KOH solution, you will need to dissolve the appropriate amount of potassium hydroxide (KOH) pellets in a specific volume of anhydrous ethanol. First, calculate the molecular weight of KOH (39.10 g/mol) and then measure out the required weight to make a 1N solution. Once weighed, slowly add the KOH pellets into the anhydrous ethanol while stirring until fully dissolved. Check the final volume to ensure it reaches 1N concentration. Remember to handle KOH with care as it is caustic and generate heat when dissolving in ethanol.
The reaction between HBr and KOH is a 1:1 ratio. This means that the moles of HBr present in the solution will be equal to the moles of KOH used in the neutralization reaction. Using this information and the volume and concentration of KOH used, you can calculate the concentration of the HBr solution.
The answer is10,436 g.
Yes, KOH (potassium hydroxide) in water exists as an aqueous solution.
To find the molarity of the KOH solution, we first need to determine the number of moles of HCl used in the reaction (n(HCl) = Molarity x Volume). Then, since KOH and HCl react in a 1:1 ratio, the number of moles of KOH will be the same. Finally, calculate the molarity of KOH using the moles of KOH and the volume of KOH solution used.
-log(1.0 X 10^-4 M KOH) = 4 14 - 4 = 10 pH KOH ----------------