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To find the molarity (M) of the KOH solution, first calculate the number of moles of KOH. The molar mass of KOH is approximately 56.11 g/mol. Therefore, 28 g of KOH corresponds to about 0.498 moles (28 g ÷ 56.11 g/mol). Finally, the molarity is calculated as moles of solute per liter of solution: ( M = \frac{0.498 \text{ moles}}{2 \text{ L}} = 0.249 , M ). Thus, the molarity of the solution is approximately 0.25 M.

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