NaOH is a base so it will produce a pH above 7.
Sodium hydroxide is an alkali; the pH of the solution is over 7.
a pH=10 solution of NaOH should contain 0,0001 moles of NaOH/liter. (1 mole/liter for pH=14, 0,1 for pH=13, etc.) A mole of NaOH is 40g-s. (Na=23g O=16g H=1g) 0,0001 mole is 0,004gs. You need the amount necessary for a quarter of a liter, so you divide by four. The result is that you need 0,001gs of NaOH. So if you need to make that solution without any precise laboratory equipment, you should make much larger quantities and just measure 0,250 l-s.
HCl : makes it acidic. it decreases the pH NaOH : makes it alkaline. it increases the pH
This solution contain 26,3 g NaOH.
The pH value for this solution is 13.
11.3
A 0.01 M solution of NaOH has a pH =13
-log(10^-4 M NaOH) = 4 14 - 4 = 10 pH NaOH -----------------------
13.51
13
concentrated solution of NaOH and KOH have the pH value about 13.
THE PH VALUE ACIDIC SOLUTION VARIOUS FROM 0-6.9, WHILE THE BASIC SOLUTION VARIOUS FROM 7.1-1.4. THUS ,OUT OF HCL AND NaOH WILL HIGHER PH VALUE
No, sodium hydroxide (NaOH) does not have a pH of 7. Sodium hydroxide is a strong base and has a pH greater than 7. The pH of a solution of sodium hydroxide depends on its concentration. A 0.1 M solution of NaOH has a pH of 13.
1 millimolar = 0.001 M NaOH ( a base, remember ) - log(0.001 M NaOH) = 3 14 - 3 = 11 pH ----------
Yes, a concentrated solution of NaOH and KOH may have pH=14
pH=12.