-log(10^-4 M NaOH)
= 4
14 - 4
= 10 pH NaOH
-----------------------
A 0.01 M solution of NaOH has a pH =13
13.51
- log(0.048 M NaOH) = 1.3 pH --------------need Molarity? 1/10 1.3 = 0.050 M H3O ---------------------
THE PH VALUE ACIDIC SOLUTION VARIOUS FROM 0-6.9, WHILE THE BASIC SOLUTION VARIOUS FROM 7.1-1.4. THUS ,OUT OF HCL AND NaOH WILL HIGHER PH VALUE
Can use this way. -log(0.001) = 3 14 - 3 = a pH of 11.0
A 0.01 M solution of NaOH has a pH =13
13.51
1 millimolar = 0.001 M NaOH ( a base, remember ) - log(0.001 M NaOH) = 3 14 - 3 = 11 pH ----------
No, sodium hydroxide (NaOH) does not have a pH of 7. Sodium hydroxide is a strong base and has a pH greater than 7. The pH of a solution of sodium hydroxide depends on its concentration. A 0.1 M solution of NaOH has a pH of 13.
- log(0.048 M NaOH) = 1.3 pH --------------need Molarity? 1/10 1.3 = 0.050 M H3O ---------------------
THE PH VALUE ACIDIC SOLUTION VARIOUS FROM 0-6.9, WHILE THE BASIC SOLUTION VARIOUS FROM 7.1-1.4. THUS ,OUT OF HCL AND NaOH WILL HIGHER PH VALUE
Can use this way. -log(0.001) = 3 14 - 3 = a pH of 11.0
5.7
5.7
base
13
12.97