To find the pH of a 0.6 M NaOH solution, first, note that NaOH is a strong base that dissociates completely in water. The concentration of hydroxide ions (OH⁻) will also be 0.6 M. The pOH can be calculated as -log(0.6), which is approximately 0.22. Since pH + pOH = 14, the pH of the solution is about 13.78.
To prepare a 5 M NaOH solution, measure out 200 g of NaOH pellets and dissolve them in enough water to make 1 liter of solution. To adjust the pH to 12, you can titrate the solution with a standard acid solution (e.g. HCl) until the desired pH is reached. Remember to wear appropriate safety gear and use a fume hood when working with NaOH.
NaOH is a base so it will produce a pH above 7.
pH = -log10[H] so 1.96 x 10-2 = -1.71 so 1.71. pH + pOH = 14 14 - 1.71 = 12.29
Sodium hydroxide is an alkali; the pH of the solution is over 7.
To calculate the pH after each volume of NaOH is added, you need to determine the moles of HBr initially, moles of NaOH added, and then use these values to calculate the final concentration of H3O+ ions in the solution. From there, you can calculate the pH using the equation pH = -log[H3O+]. Repeat these calculations for each volume of NaOH added to find the pH at 12.5 ml, 18.7 ml, 20.0 ml, 29.5 ml, and 34.2 ml.
The pH of a 0.001N NaOH solution is around 11.9. NaOH is a strong base, and at this concentration, it will result in a highly alkaline solution.
The pH of a 2.34x10^-5 NaOH solution is 12.33 (calculated as -log[OH^-]). The pOH of the same solution is 1.67 (calculated as -log[NaOH]).
The pH of a 0.002M solution of NaOH is around 11.98. This is because NaOH is a strong base that dissociates completely in water to produce hydroxide ions, which lead to the alkaline pH.
-log(10^-4 M NaOH) = 4 14 - 4 = 10 pH NaOH -----------------------
The pH of a 0.1M NaOH solution is around 13. NaOH is a strong base that dissociates completely in water to produce hydroxide ions, leading to a highly alkaline environment with a high pH value.
The pH of a 1.0 x 10^-6 M NaOH solution is approximately 11.00. This is because NaOH is a strong base that dissociates completely in solution to produce hydroxide ions, resulting in a high pH.
Adding a small amount of NaOH to a buffer solution will increase the pH of the solution. This is because NaOH is a strong base that will react with the weak acid in the buffer, causing the pH to rise.
The pH of a 1 millimolar NaOH solution is approximately 11. The concentration of a 1 millimolar solution is 0.001 mol/L, and NaOH is a strong base that completely dissociates in water to produce hydroxide ions, leading to a basic pH.
The pH of a 0.33 M solution of NaOH is approximately 13.5. This is because NaOH is a strong base that dissociates completely in water to give hydroxide ions, which results in a highly alkaline solution.
THE PH VALUE ACIDIC SOLUTION VARIOUS FROM 0-6.9, WHILE THE BASIC SOLUTION VARIOUS FROM 7.1-1.4. THUS ,OUT OF HCL AND NaOH WILL HIGHER PH VALUE
The pH of a solution of NaOH (sodium hydroxide) is approximately 14, as it is a strong base. This means it is highly alkaline.
The pH of a 0.1 M NaOH solution is approximately 13. NaOH is a strong base that dissociates completely in water to produce hydroxide ions, which results in a highly alkaline solution with a pH greater than 7.