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Prepare 5 M NaOH of pH 12?
To prepare a 5 M NaOH solution, measure out 200 g of NaOH pellets and dissolve them in enough water to make 1 liter of solution. To adjust the pH to 12, you can titrate the solution with a standard acid solution (e.g. HCl) until the desired pH is reached. Remember to wear appropriate safety gear and use a fume hood when working with NaOH.
What would happen to the solubility of potassium chloride in water as the water temperature increased from 25 and degC to 100 and degC?
The solubility increase from 38,7 g KCl/100g water to 40,7 g KCl/100 g water.
What is of 25 m mol solution?
A 25 millimole (m mol) solution means there are 25 millimoles of solute in every liter of solution. It is a unit used to express the concentration of a solute in a solution.
Room temperature is usually considered to be 25 and degC. What is that in kelvins?
Room temperature, typically around 25°C, can be converted to kelvins using the formula K = °C + 273.15. Therefore, 25°C is equivalent to 25 + 273.15 = 298.15 K. Thus, room temperature in kelvins is approximately 298.15 K.
How much water must be added to 40 ml of a 25 percent by weight solution to make a 2 percent by weight solution?
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
What is the molarity of a solution made by dissolving 25 grams of Mg in excess NaOH solution?
The molarity of the solution is 0.5 M.
Prepare 5 M NaOH of pH 12?
To prepare a 5 M NaOH solution, measure out 200 g of NaOH pellets and dissolve them in enough water to make 1 liter of solution. To adjust the pH to 12, you can titrate the solution with a standard acid solution (e.g. HCl) until the desired pH is reached. Remember to wear appropriate safety gear and use a fume hood when working with NaOH.
When A balloon has a volume of 10500 liters and the temperature is 15 and degC. If the temperature were -25 and degC what would the volume of the balloon be?
It would be approx 9042 litres.
What is the Ka value of NaOH?
The Ka value is a measure of the strength of an acid in solution, not a base like NaOH. Instead, the strength of a base is typically measured using the Kb value. However, if you are asking about the dissociation constant of NaOH in water, it would be the Kw value, which is equal to 1.0 x 10^-14 at 25 degrees Celsius.
Calculate the pH of solution formed when 30cm3 of 0.125m naoh are reacted with 25cm3 of 0.15m hcl at 298k?
No. of mol of NaOH used = 30/1000 x 0.125 = 0.00375No. of mol of HCl used = 25/1000 x 0.15 = 0.00375No. of mol of HCl used = No. of mol of NaOH used.Hence, the resultant solution will be neutral. pH ~ 7.(NaCl formed is a neutral salt, does not undergo any form of salt hydrolysis)
How procedure of NaoH are required to prepare 0.25 L of 0.5 M of solution?
Well, isn't that a happy little question! To prepare 0.25 L of 0.5 M NaOH solution, you'll need to dissolve the correct amount of NaOH in water. You can use the formula C1V1 = C2V2 to calculate the amount of NaOH needed. Just take your time, follow the steps gently, and you'll have a perfect solution in no time.
A student carefully diluted 25.0 ml 0.6 M NaOH solution in 475 ml of distilled water What is the molarity of the diluted solution of base?
Assuming that the 25.0 ml are added to the 475 ml of water, not diluted to that volume:Moles of NaOH in the original 25 ml = 25/1000 x 0.6 = 0.015 moles Final volume = 25 + 475 ml = 500 ml. We have 0.015 moles in 500 ml, so 0.03 moles in a litre, Molarity = 0.03.
What would happen to the solubility of potassium chloride in water as the water temperature increased from 25 and degC to 100 and degC?
The solubility increase from 38,7 g KCl/100g water to 40,7 g KCl/100 g water.
What is of 25 m mol solution?
A 25 millimole (m mol) solution means there are 25 millimoles of solute in every liter of solution. It is a unit used to express the concentration of a solute in a solution.
What is x-25?
[ x - 25 ] has no solution.
What is X.25?
[ x - 25 ] has no solution.
How do you find pH and poh of a 0.002614M NaOH solution?
First, since NaOH is a base you have to find the pOH first so you use the equation -> pOH = -log[NaOH] pOH = -log[NaOH] = -log[0.0111] pOH = 1.955 Then you use this equation -> 14 = pH + pOH to find the pH 14 = pH + pOH pH = 14 - pOH = 14 - 1.955 pH = 12.045 and that makes it basic Hope that helped. ^_^
