First, since NaOH is a base you have to find the pOH first
so you use the equation -> pOH = -log[NaOH]
pOH = -log[NaOH]
= -log[0.0111]
pOH = 1.955
Then you use this equation -> 14 = pH + pOH to find the pH
14 = pH + pOH
pH = 14 - pOH
= 14 - 1.955
pH = 12.045
and that makes it basic
Hope that helped. ^_^
The pH of a 2.34x10^-5 NaOH solution is 12.33 (calculated as -log[OH^-]). The pOH of the same solution is 1.67 (calculated as -log[NaOH]).
To calculate the pH of a 0.001 M NaOH solution, you can use the formula pH = 14 - pOH. Since NaOH is a strong base that completely dissociates in water, the pOH can be directly calculated as -log(0.001) = 3. Thus, the pH of the solution would be 14 - 3 = 11.
The pOH is 6,4.
The pH of a 1.0 M NaOH solution is approximately 14. NaOH is a strong base that dissociates completely in water to produce hydroxide ions, resulting in a highly alkaline solution with a pH at the upper end of the scale.
pH + pOH = 14 If the pH is 3.4, the pOH is 10.6
The pH of a 2.34x10^-5 NaOH solution is 12.33 (calculated as -log[OH^-]). The pOH of the same solution is 1.67 (calculated as -log[NaOH]).
To find the pH of a 0.6 M NaOH solution, first, note that NaOH is a strong base that dissociates completely in water. The concentration of hydroxide ions (OH⁻) will also be 0.6 M. The pOH can be calculated as -log(0.6), which is approximately 0.22. Since pH + pOH = 14, the pH of the solution is about 13.78.
5.7
To find the pOH of a solution, you can use the formula pOH = -log[OH⁻]. Given that [OH⁻] = 1.41 × 10⁻¹³, calculate the pOH: pOH = -log(1.41 × 10⁻¹³) ≈ 12.85. Therefore, the pOH of the solution is approximately 12.85.
To find the pOH of a solution, you can use the relationship between pH and pOH, which is given by the equation: pH + pOH = 14. If the pH of the solution is 6.2, then the pOH can be calculated as follows: pOH = 14 - pH = 14 - 6.2 = 7.8. Therefore, the pOH of the solution is 7.8.
To calculate the pH of a 0.001 M NaOH solution, you can use the formula pH = 14 - pOH. Since NaOH is a strong base that completely dissociates in water, the pOH can be directly calculated as -log(0.001) = 3. Thus, the pH of the solution would be 14 - 3 = 11.
The pOH is 6,4.
To find the pOH of a solution, you can use the formula pOH = -log[OH⁻]. Given that the hydroxide ion concentration [OH⁻] is 9.0 × 10⁻⁷ M, the pOH can be calculated as follows: pOH = -log(9.0 × 10⁻⁷) ≈ 6.05. Thus, the pOH of the solution is approximately 6.05.
To find the pOH of a solution, you can use the formula pOH = -log[OH⁻]. Given that the concentration of hydroxide ions [OH⁻] is 2.010 × 10⁻² M, you would calculate pOH as follows: pOH = -log(2.010 × 10⁻²) ≈ 1.69. Thus, the pOH of the solution is approximately 1.69.
The pH of a 1.0 M NaOH solution is approximately 14. NaOH is a strong base that dissociates completely in water to produce hydroxide ions, resulting in a highly alkaline solution with a pH at the upper end of the scale.
The pOH of the solution would be 6. If you subtract the pOH from 14 (pH + pOH = 14), you would find that the pH of the solution is 8.
pH + pOH = 14 If the pH is 3.4, the pOH is 10.6