First, since NaOH is a base you have to find the pOH first
so you use the equation -> pOH = -log[NaOH]
pOH = -log[NaOH]
= -log[0.0111]
pOH = 1.955
Then you use this equation -> 14 = pH + pOH to find the pH
14 = pH + pOH
pH = 14 - pOH
= 14 - 1.955
pH = 12.045
and that makes it basic
Hope that helped. ^_^
At first calculate pOH from [OH-], the substract this value from 14.
So:
pOH = -log[OH-]= -log[0.002614] = -[-3 + log(2.614)] = 2.58 = 2.6 = pOH
Then, from pH + pOH = 14 (at 25 0C) it follows that pH = 14.0 - pOH = 14.0 - 2.6 = 11.4 = pH
-log(0.001 NaOH)
= 3 subtracted from 14
= 11 pH
pH=10, so pOH=14-10=4 [OH]=10^-pOH [OH]=10^-4 [OH]=0.0001
Supposed the acid and base are both strong: pH of the acid is 0.0 and the pH of the base (hydroxide) is 14.0
pH would decrease since H+ concentration increases, while pOH would increase since OH- concentration decreases. But pH would always be above 7 and pOH would always be below 7 since H+ will never be equal to OH- [OH-] would be always be greater than [H+] in any solution of NaOH , however dilute. Also remember pH + pOH =14, thus if pH decreases then pOH increases. Thanking you Yours Rajiv
The pOH is 5,23.
pOH +pH=14 pOH+7.6=14 pOH=(14-7.6)=6.4
5.7
pH=10, so pOH=14-10=4 [OH]=10^-pOH [OH]=10^-4 [OH]=0.0001
1 millimolar = 0.001 M NaOH ( a base, remember ) - log(0.001 M NaOH) = 3 14 - 3 = 11 pH ----------
3
The pOH is 8,7.
The pOH is 8,7.
The pOH is 8,7.
The pH and pOH are related to each other through the equation: pH + pOH = 14 If the pH of a solution is 3, we can find the pOH by rearranging the above equation: pOH = 14 - pH = 14 - 3 = 11 Therefore, the pOH of the solution is 11.
Supposed the acid and base are both strong: pH of the acid is 0.0 and the pH of the base (hydroxide) is 14.0
pH would decrease since H+ concentration increases, while pOH would increase since OH- concentration decreases. But pH would always be above 7 and pOH would always be below 7 since H+ will never be equal to OH- [OH-] would be always be greater than [H+] in any solution of NaOH , however dilute. Also remember pH + pOH =14, thus if pH decreases then pOH increases. Thanking you Yours Rajiv
The pOH is 5,23.
12.85 is the pOH.