pH is 8
Molarity = moles of solute/liters of solution ( 300 ml = 0.300 liter ) 0.250 molar KOH = moles KOH/0.300 liters = 0.075 moles KOH
Molarity = moles of solute/liters of solution M = 10 mol NaOH/1 liter = 10 M -log(10 M) = -1 14 - (-1) = 15 pH sodium hydroxide
n=c/v n=3M/.25L n=12 mol m=Mxn m=58.443 g/mol x 12 mol m=701.3 g n= mol c=concentration v=volume m=mass M= molar mass Tylerops: I don't agree with this answer. Molarity is defined as Moles/Liters. In other words Molarity is the concentration of a solution. In the above n= Concentration / Liters. That is equal to saying Moles=(Moles/liters)/ Liters. In the above question the concentration is (3 moles/ liter), or 3M. Plus, how can it be possible to have 12 moles in 250ml when you only have 3 moles in each liter of the original solution? Correct ANSWER: 3.00 M, or 3 moles per (L) "liter" calls for having 3 moles per liter of the solution. The question asks how many moles must be in 250ml of a solution that has 3 moles per Liter. You must ask yourself what percent of 1 Liter is 250mls? Since there are a thousand ml in one liter, (1000ml=1L), then 250ml is exactly 25% of a Liter, or .25L. So, 250ml can only hold 25% of the 3.00 Molarity. Meaning that you multiply 3 x .25 and get .75 moles. 58.443g/molNaCl x .75 moles = FINAL ANSWER 43.83225g NaCl, Sig Fig, 43.83gNaCl
To prepare 6 nM ammonium hydroxide a 30 percent solution you need to know the volume of the 30 percent solution that you have and the volume of 6nM solution you would like to make. Then use the following formula: C1V1 = C2V2 where C = concentration in moles/Liter and V = volume in liters.
3.00 M, or 3 moles per (L) "liter" calls for having 3 moles per liter of the solution. The question asks how many moles must be in 250ml of a solution that has 3 moles per Liter. You must ask yourself what percent of 1 Liter is 250mls? Since there are a thousand ml in one liter, (1000ml=1L), then 250ml is exactly 25% of a Liter, or .25L. So, 250ml can only hold 25% of the 3.00 Molarity. Meaning that you multiply 3 x .25 and get .75 moles.
You need 1,25 moles ammonia.
8.42 grams of KOH is equal to 0.15 moles. If the solution has a molarity of 2.26 moles per liter, then there are 66.4 milliliters of solution.
Molarity = moles of solute/liters of solution ( 300 ml = 0.300 liter ) 0.250 molar KOH = moles KOH/0.300 liters = 0.075 moles KOH
Molarity = moles of solute/liters of solution M = 10 mol NaOH/1 liter = 10 M -log(10 M) = -1 14 - (-1) = 15 pH sodium hydroxide
n=c/v n=3M/.25L n=12 mol m=Mxn m=58.443 g/mol x 12 mol m=701.3 g n= mol c=concentration v=volume m=mass M= molar mass Tylerops: I don't agree with this answer. Molarity is defined as Moles/Liters. In other words Molarity is the concentration of a solution. In the above n= Concentration / Liters. That is equal to saying Moles=(Moles/liters)/ Liters. In the above question the concentration is (3 moles/ liter), or 3M. Plus, how can it be possible to have 12 moles in 250ml when you only have 3 moles in each liter of the original solution? Correct ANSWER: 3.00 M, or 3 moles per (L) "liter" calls for having 3 moles per liter of the solution. The question asks how many moles must be in 250ml of a solution that has 3 moles per Liter. You must ask yourself what percent of 1 Liter is 250mls? Since there are a thousand ml in one liter, (1000ml=1L), then 250ml is exactly 25% of a Liter, or .25L. So, 250ml can only hold 25% of the 3.00 Molarity. Meaning that you multiply 3 x .25 and get .75 moles. 58.443g/molNaCl x .75 moles = FINAL ANSWER 43.83225g NaCl, Sig Fig, 43.83gNaCl
Assuming that by M you mean moles per liter, you have described a solution with a pH of 10, which is strongly alkaline.
A neutral solution can contain ions of hydrogen, hydroxide, and the cation and anion of any neutral salt. There are equal numbers of hydrogen and hydroxide ions, and also an equal (but usually different) number of the other pair of ions.
0.1 moles
The 0.5M and 2M refer to moles per liter (of solution). Volume of final solution is 2.5 L + 500 mL = 2.5 L + 0.5 L = 3.0 L. So find out how many moles the final solution has and divide by 3.0L.First solution (0.5 moles/liter)*(2.5 liter) = 1.25 moles2nd solution (2 moles/liter)*(0.5 liter) = 1 moleMolarity: (1.25 mole + 1 mole)/(3.0 liter) = 0.75 moles/liter = 0.75 M
Depends on the concentration of the solution and what is in it.
The molarity of a solution is the number of moles of a solute per liter of its solution. The normality of a solution is the number of gram equivalent weight of a solute per liter of its solution. As I said before, and precisely, Molarity is moles of solute per VOLUME of solution!
A neutral solution of about 7 pH.