The pH of a 2.34x10^-5 NaOH solution is 12.33 (calculated as -log[OH^-]). The pOH of the same solution is 1.67 (calculated as -log[NaOH]).
First, since NaOH is a base you have to find the pOH first so you use the equation -> pOH = -log[NaOH] pOH = -log[NaOH] = -log[0.0111] pOH = 1.955 Then you use this equation -> 14 = pH + pOH to find the pH 14 = pH + pOH pH = 14 - pOH = 14 - 1.955 pH = 12.045 and that makes it basic Hope that helped. ^_^
To calculate the pH of a 0.001 M NaOH solution, you can use the formula pH = 14 - pOH. Since NaOH is a strong base that completely dissociates in water, the pOH can be directly calculated as -log(0.001) = 3. Thus, the pH of the solution would be 14 - 3 = 11.
The pH of a 1.0 M NaOH solution is approximately 14. NaOH is a strong base that dissociates completely in water to produce hydroxide ions, resulting in a highly alkaline solution with a pH at the upper end of the scale.
The pOH is 6,4.
To prepare a solution with a pH of 10.00, you will need to calculate the concentration of hydroxide ions. Once you have this concentration, you can determine the amount of NaOH needed to achieve this pH in 546 mL of solution.
First, since NaOH is a base you have to find the pOH first so you use the equation -> pOH = -log[NaOH] pOH = -log[NaOH] = -log[0.0111] pOH = 1.955 Then you use this equation -> 14 = pH + pOH to find the pH 14 = pH + pOH pH = 14 - pOH = 14 - 1.955 pH = 12.045 and that makes it basic Hope that helped. ^_^
To find the pH of a 0.6 M NaOH solution, first, note that NaOH is a strong base that dissociates completely in water. The concentration of hydroxide ions (OH⁻) will also be 0.6 M. The pOH can be calculated as -log(0.6), which is approximately 0.22. Since pH + pOH = 14, the pH of the solution is about 13.78.
To calculate the pH of a 0.001 M NaOH solution, you can use the formula pH = 14 - pOH. Since NaOH is a strong base that completely dissociates in water, the pOH can be directly calculated as -log(0.001) = 3. Thus, the pH of the solution would be 14 - 3 = 11.
The pH of a 1 millimolar NaOH solution is approximately 11. The concentration of a 1 millimolar solution is 0.001 mol/L, and NaOH is a strong base that completely dissociates in water to produce hydroxide ions, leading to a basic pH.
The pH of a 1.0 M NaOH solution is approximately 14. NaOH is a strong base that dissociates completely in water to produce hydroxide ions, resulting in a highly alkaline solution with a pH at the upper end of the scale.
To find the pOH of a solution, you can use the relationship between pH and pOH, which is given by the equation: pH + pOH = 14. If the pH of the solution is 6.2, then the pOH can be calculated as follows: pOH = 14 - pH = 14 - 6.2 = 7.8. Therefore, the pOH of the solution is 7.8.
The pOH is 6,4.
To prepare a solution with a pH of 10.00, you will need to calculate the concentration of hydroxide ions. Once you have this concentration, you can determine the amount of NaOH needed to achieve this pH in 546 mL of solution.
The pOH of a solution can be calculated using the formula: pOH = 14 - pH. For a solution with a pH of 6.2, the pOH would be 14 - 6.2 = 7.8.
The pOH of a solution can be calculated using the formula pOH = 14 - pH. Therefore, if the pH of a solution is 12.2, the pOH would be 14 - 12.2 = 1.8.
pH + pOH = 145.3 + pOH = 14pOH = 14 - 5.3pOH = 8.7
1.8