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A solution of HCl has H 2.5 x 10-5 What is the pOH of this solution?
Kclark71
pH + pOH = 14
If the pH is 3.4, the pOH is 10.6
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∙ 14y ago
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What volume of 12M HCl solution is needed to prepare 250 mL of 0.100M solution?
25 mL
What is the OH- of a solution with pH 5.75?
pOH = -log[OH-] = -log(5*10^-3) = 2.3 pH = 14 - pOH = 14.0 - 2.3 = 11.7 (at 25 oC)
How do you make 25 ml of a 0.0010 M HCl starting with 0.010 M HCl?
V = volume, M = molarity V1M1=V2M2 (25 mL)(0.0010 M) = (x)(0.010 M) x = (25 mL)(0.0010 M)/(0.010 M) x = 2.5 mL To make a 25 mL 0.0010 M HCl solution with 0.010 M HCl, you would measure out 2.5 mL of the 0.010 M HCl in a 25 mL graduated cylinder (or laboratory equipment of your choice) and then add 22.5 mL of distilled water.
How many moles of HCL gas are contained in 25 ml of a 0.10 M solution of the acid?
you cant solve that without the concentration of the HCl or the mass if you have either of these use: To find the moles with mass of HCl you have use n= m/mm , m=mass of HCl and mm = the molar mass so the elements mass combined from periodic table to find the moles with the volume = 0.06 (in litres must be!) and concentration use n = cv
How do you find pH and poh of a 0.002614M NaOH solution?
First, since NaOH is a base you have to find the pOH first so you use the equation -> pOH = -log[NaOH] pOH = -log[NaOH] = -log[0.0111] pOH = 1.955 Then you use this equation -> 14 = pH + pOH to find the pH 14 = pH + pOH pH = 14 - pOH = 14 - 1.955 pH = 12.045 and that makes it basic Hope that helped. ^_^
What volume of 12M HCl solution is needed to prepare 250 mL of 0.100M solution?
25 mL
What is the sum of pH and pOH in any solution?
ONLY in pure water at 25 0C :pH + pOH = 14.00
What is the OH- of a solution with pH 5.75?
pOH = -log[OH-] = -log(5*10^-3) = 2.3 pH = 14 - pOH = 14.0 - 2.3 = 11.7 (at 25 oC)
How do you make 25 ml of a 0.0010 M HCl starting with 0.010 M HCl?
V = volume, M = molarity V1M1=V2M2 (25 mL)(0.0010 M) = (x)(0.010 M) x = (25 mL)(0.0010 M)/(0.010 M) x = 2.5 mL To make a 25 mL 0.0010 M HCl solution with 0.010 M HCl, you would measure out 2.5 mL of the 0.010 M HCl in a 25 mL graduated cylinder (or laboratory equipment of your choice) and then add 22.5 mL of distilled water.
How many moles of HCL gas are contained in 25 ml of a 0.10 M solution of the acid?
you cant solve that without the concentration of the HCl or the mass if you have either of these use: To find the moles with mass of HCl you have use n= m/mm , m=mass of HCl and mm = the molar mass so the elements mass combined from periodic table to find the moles with the volume = 0.06 (in litres must be!) and concentration use n = cv
How do you find pH and poh of a 0.002614M NaOH solution?
First, since NaOH is a base you have to find the pOH first so you use the equation -> pOH = -log[NaOH] pOH = -log[NaOH] = -log[0.0111] pOH = 1.955 Then you use this equation -> 14 = pH + pOH to find the pH 14 = pH + pOH pH = 14 - pOH = 14 - 1.955 pH = 12.045 and that makes it basic Hope that helped. ^_^
The LCM of 25 and 105?
525 is the LCM of 25 and 105
What is the pH of neutral solution at 25 degrees Celsius?
pOH= -log(0.0025) this equals +2.6. The pH scale is reversed, so 14-2.6 = +11.4. 11.4 is the answer
Can 105 divide into 25?
4.2
What percent of 25 is 10.5?
105 is what percent of 25= 105 / 25= 4.2Converting decimal to a percentage: 4.2 * 100 = 420%
What is the LCM of 105 and 25?
The LCM is 525.
What is example of quantitative observation?
Quantitative observations involve numbers. An example would be the volume of 0.1M HCl needed to neutralise 25 ml of sodium hydroxide solution.
