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pH =pKa - log [ cA / cB ]

where:

pKa is the negative logarithmic value of the weak acid equilibrium consant,

cA is the molar concentration of the weak acid conjugate (acetic acid) and

cB is the molar concentration of the weak base conjugate (acetate).

So

pH = 4.77 -log(0.16 / 0.23) = 4.77 - ( -0.158) = 4.77 + 0.158 = 4.93

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13y ago
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AnswerBot

6d ago

To calculate the pH of the solution, you need to consider the dissociation of both acids. Nitrous acid (HNO2) is a weak acid, while sodium nitrite (NaNO2) is a salt of a weak acid. Use the given concentrations to calculate the initial concentration of H+ ions from HNO2, then consider the effect of the NaNO2 on the pH by reacting with any excess H+ ions. Finally, calculate the pH using the equilibrium concentrations of the resulting species.

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12y ago

1.0e-07

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Q: What is the pH of a solution containing 0.16 m hno2 and 0.50 m nano2?
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