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What is the pH of a solution containing 0.16 m hno2 and 0.50 m nano2?
Wiki User
∙ 12y ago
pH =pKa - log [ cA / cB ]
where:
pKa is the negative logarithmic value of the weak acid equilibrium consant,
cA is the molar concentration of the weak acid conjugate (acetic acid) and
cB is the molar concentration of the weak base conjugate (acetate).
So
pH = 4.77 -log(0.16 / 0.23) = 4.77 - ( -0.158) = 4.77 + 0.158 = 4.93
Wiki User
∙ 13y ago
Wiki User
∙ 12y ago1.0e-07
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