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By definition: pH = -log[H3O+]So pH = -log(7.4*10-9) = 8.13
pH = -log[H3O+] = -log(7.9*10^-11) = 10.1
pH = (by definition) = -log10[H3O+] , no matter what kind of acid,This inverted to:[H3O+] = 10-pH = becomes 10-2.9 = 1.3*10-3 mol/lNote: [H3O+] = concentration of hydronium ions (mol/l),which is the same as (or equivalent with) saying H+ ions concentration in water
5.0 x 10-3 pH = - log [H3O+] [H3O+] = 1 x 10^-pH pH = 2.3 [H3O+] = 1 x 10^(-2.3) = 5 x 10^(-3) M
2 x 10-10 M
By definition: pH = -log[H3O+]So pH = -log(7.4*10-9) = 8.13
pH = 6.0 at 25 oC when water equilibrium is taken into account correctly.
pH = -log[H3O+] = -log(7.9*10^-11) = 10.1
In an aqueous solution, the concentration of H3O+ is the same as the concentration of H+. If you know the pH of the solution, then that's equal to 10^(-pH).
The pH of a neutral solution is 7 and the concentration of H+ or H3O+ in the solution would be 1.0 X 10-7.
pH = -log(hydronium concentration) [Hydronium is H3O.-log(1 x 10-9) = 9
pH = (by definition) = -log10[H3O+] , no matter what kind of acid,This inverted to:[H3O+] = 10-pH = becomes 10-2.9 = 1.3*10-3 mol/lNote: [H3O+] = concentration of hydronium ions (mol/l),which is the same as (or equivalent with) saying H+ ions concentration in water
5.0 x 10-3 pH = - log [H3O+] [H3O+] = 1 x 10^-pH pH = 2.3 [H3O+] = 1 x 10^(-2.3) = 5 x 10^(-3) M
2 x 10-10 M
pH = 4. The reason is that pH = -log [H+] or -log [H3O+] = -log 10^-4 = 4.
1.39
It has 10 times as many. pH is roughly the same as "log [H3O+]". This means "10 to what power is equal to the concentration of H3O+ ions?" So, if you go from pH 5 to pH 4, you've got a concentration of ten times fewer H3O+ ions, and ten times more H+ ions.