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1 hp = 745.7 watts, so 75 hp = 55.93 kilowatts
Kw value of water is 1.0*10-14 moles2/L2 at room temperature. So the H3O+ ion concentration is 10-7 moles/L.
12HP is approximately 10.8 KVA. You would want to use a 15KVA transformer to supply this motor. KW = HP * .75 KVA = KW * 1.2 (These formulas are approximate)
AnswerKiloWatt hours. Its a measure of energy use. It is the amount of power used over time.Energy is the ability to do work, while power is the rate at which work is done.Your water heater may have a power rating of 5 kW. If it runs for 8 hours in a day, you would use 40 kWh of energy doing the work of heating the water.
Electricity is sold in kilowatt hours in typical residential settings. A range of costs is from about 10 to 15 cents per kw hr.
75 hp is about 56 kW
0.0075 kw
Multiply by Amps.
Kw = [H+][OH-] [H+] = 10-pH = 10-6.17 For [OH-] remember that heat causes more water molecules to self-dissociate but for every new H+ generated, a OH- is generated as well. Therefore, the concentration of H+ and OH- is equal. [OH-] = 10-6.17 Kw = [H+][OH-] = 10-6.17 * 10-6.17 = 10-12.34
starting current of 3 phase 75 KW induction motor
3phese 460 volt 75 kw a/c drivi full load current
Kw is the ionisation constant for water at 25°C which value is 1.0x10^-14. (chemistry)In water at any pH the equilibrium state Kw is defined by and equal to the 'ion product':Kw = [H3O+]*[OH-] = 1.0*10-14at room temperature 25°C
1 MW is 1000 kW therefore 10 MW is equal to 10,000 kW.
1.0*10^-14 No Units
Kw = [H+][OH-][H+] = 10-pH = 10-7.56In neutral pure water the concentration of H+ and OH- is equal.[OH-] = 10-7.56Kw = [H+][OH-] = 10-7.56 * 10-7.56 = 10-15.12
1 hp = 745.7 watts, so 75 hp = 55.93 kilowatts
Kw value of water is 1.0*10-14 moles2/L2 at room temperature. So the H3O+ ion concentration is 10-7 moles/L.