1.70
To find the pOH of a solution, you can use the formula pOH = -log[OH⁻]. Given that [OH⁻] = 1.41 × 10⁻¹³, calculate the pOH: pOH = -log(1.41 × 10⁻¹³) ≈ 12.85. Therefore, the pOH of the solution is approximately 12.85.
To find the pOH of a solution, you can use the formula pOH = -log[OH⁻]. Given that the hydroxide ion concentration [OH⁻] is 9.0 × 10⁻⁷ M, the pOH can be calculated as follows: pOH = -log(9.0 × 10⁻⁷) ≈ 6.05. Thus, the pOH of the solution is approximately 6.05.
To find the pOH of a solution, you can use the formula pOH = -log[OH⁻]. Given that the concentration of hydroxide ions [OH⁻] is 2.010 × 10⁻² M, you would calculate pOH as follows: pOH = -log(2.010 × 10⁻²) ≈ 1.69. Thus, the pOH of the solution is approximately 1.69.
To find the pOH from the hydroxide ion concentration (OH⁻), use the formula pOH = -log[OH⁻]. Given [OH⁻] = 2.0 × 10⁻² M, the calculation is pOH = -log(2.0 × 10⁻²) ≈ 1.70. Thus, the pOH of the solution is approximately 1.70.
12.85 is the pOH.
1.70
To find the concentration of hydroxide ions (OH⁻) in a solution with a pH of 11.70, first, calculate the pOH using the formula pOH = 14 - pH. This gives pOH = 14 - 11.70 = 2.30. Then, use the relationship between pOH and hydroxide concentration: OH⁻ = 10^(-pOH). Therefore, the concentration of OH⁻ is approximately 0.00512 M.
1.70
The pOH can be calculated using the formula pOH = -log[OH-]. In this case, pOH = -log(9.0 x 10^-7) ≈ 6.05.
To find the concentration of hydroxide ions ([OH-]) in a solution when the pH is 4.0, you can use the formula pH + pOH = 14. Since the pH is 4.0, the pOH would be 14 - 4 = 10. To convert pOH to [OH-] concentration, use the formula [OH-] = 10^(-pOH). Thus, [OH-] = 10^(-10) = 1 x 10^(-10) M.
[OH-] = 1x10^-4.22 or more conventionally, [OH-] = 6.03x10^-5 M
The pH of a solution can be calculated using the formula pH = 14 - pOH. Given that the pOH is 3.31, we can subtract this value from 14 to find the pH. In this case, the pH of the solution would be approximately 10.69.