It will have a pOH of 12. Because pH+pOH=14
It would be an acid since it is less then 7. Also, it is typically a weak acid since is it near a pH of 7 which is a neutral solution.acid
acid=1-6 nuetral=7 base=8-14 the ph scale goes from 1 to 14
on a PH scale 7 is neutral. So any number close to 7 is considered weak be it a base or an acid.
You usually calculate it with a pH stick. Good question!!.
The pH scale goes as follows : |____________|___________| 0 ACIDIC 7 BASIC 14 Below 7 = Acid More than 7 = Base
First u need to know the pH of sulfuric acid: ph= -log[h+] =-log[0.4] 0.3979 now u can find out the POH of sulfuric acid ph+poh=14 poh=14-0.3979 poh=13.6
pH is -log[H(subscript 3)O+] pOH is the [OH-] pOH = 14 - pH apex
pH 1 to 2.Sulfuric acid is a strong diprotic acid: [H+] = 2* 0.15 = 0.30 mole/L H+pH = -log 0.30 = 0.52pH 2.
1.8
I will assume you are asking about the pH of pure water if pKw is 14.26. The relationship between pH, pOH, and pKw is as follows: pH + pOH = pKw. If it is pure, neutral water (no acids or bases present), then pH = pOH, so: pH + pOH = 14.26 2(pH) = 14.26 pH = pOH = 7.13
pOH = -log(10)[OH^-] pOH = -log(10) [ 48. x 10^-2] pOH = - (-1.31875...) pOH = 1.31875... pH = 14 - pOH pH = 14 - 1.31875... pH = 12.68124... pH = 12.68
Supposed the acid and base are both strong: pH of the acid is 0.0 and the pH of the base (hydroxide) is 14.0
pH + pOH =14
The pOH is 6,4.
pH and pOH
pH + pOH =14
pH = 1 HCl is a strong acid so fully dissociates, so the concentration of H+ is equal to that of the HCl and pH=-log[H+]