If 328 grams of aluminum hydroxide react with excess hydrochloric acid how many grams of aluminum chloride can be formed?
Balanced equation first. ( you have been told the limiting
reactant. )
Al(OH)3 + 3HCl >> AlCl3 + 3H2O
Molar mass Al(OH)3 = 78.004 grams/// Molar mass AlCl3 = 133.33
grams
Conversion.
328g Al(OH)3 (1mol Al(OH)3/78.004g)(1 mol AlCl3/1mol
Al(OH)3)(133.33g AlCl3/1mol AlCl3) =560.64 grams produced