The properly written formula is Sb4O6, showing that each unit contains 4 antimony atoms and 6 oxygen atoms. The gram Atomic Mass of oxygen is 15.9994 and that of antimony is 121.75. Therefore, the percent by mass of oxygen is 100{(6)(15.994)/[(4)(121.75) + (6)(15.994)} or 16.466, to the justified number of significant digits. (The integers 4 and 6 are exact).
To find the percent composition of oxygen in Na2O, find the total molar mass of the compound. Then, divide the molar mass of oxygen by the molar mass of the compound, and multiply by 100% to get the percent oxygen.
The name of the formula Sb4O6 is Tetraantimony Hexoxide.
Oxygen atoms weigh more than Hydrogen atoms.
19.37 g/mol
Though really its just 2 moles of Sb2O3, or antimony trioxide, its Sb4O6
The percent by mass of oxygen in N2O4 is 69,56 %.
The balnced eqution for the reaction of antimony and oxygen would be 4Sb + 3O2 -> Sb4O6 Sb4O6 is the gas phase molecular form of antimony oxide, Sb2O3 and has a structure like phosphorus trioxide, P4O6
To find the percent composition of oxygen in Na2O, find the total molar mass of the compound. Then, divide the molar mass of oxygen by the molar mass of the compound, and multiply by 100% to get the percent oxygen.
The name of the formula Sb4O6 is Tetraantimony Hexoxide.
The mass percent of oxygen in SO2 is 50 %.
Estriol (C18H24O3) contain 16,644 % oxygen.
60%
The mass of the elements that are not oxygen equals 194.8g. The mass of oxygen is 230g - 194.8g = 35.2g of oxygen. Mass percent of oxygen = 35.2g O/230g x 100 = 15% O
Oxygen atoms weigh more than Hydrogen atoms.
42.3
19.37 g/mol
Because the mass of carbon is not the same as that of oxygen.