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What is the percent by volume concentration of 78.9 mL of acetone in 1550 mL of an acetone-water solution?
Wiki User
∙ 8y ago
1550 mixture-----------------78,9 acetone
100 mixture-------------------x
x = 78,9 x 100/1559 = 5,09
The concentration of acetone is 5,o9 %.
Wiki User
∙ 8y ago
The total volume of the solution is 78.9 mL + 1550 mL = 1628.9 mL. To calculate the percent by volume concentration of acetone, divide the volume of acetone by the total volume of the solution and multiply by 100. In this case, (78.9 mL / 1628.9 mL) x 100 = 4.85% volume concentration of acetone.
Wiki User
∙ 8y ago78.9 ml/1550 ml (x100) = 5.09 = 5.00% v/v
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mabey
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If 2 percent glucose solution and 5 percent glucose solution are separated by a semipermiable menbrane flows from the 2 percent glucose solution to the 5 percent glucose solution?
This process is called osmosis. Water molecules move from an area of low solute concentration (2% glucose solution) to an area of high solute concentration (5% glucose solution) to equalize the concentration on both sides of the membrane. This results in a net flow of water from the 2% glucose solution to the 5% glucose solution.
Why does the percent ionization of acetic acid increase as the concentration of the solution decreases?
As the concentration of the solution decreases, there are fewer acetic acid molecules in the solution, resulting in less competition for water molecules. This allows more acetic acid molecules to ionize, increasing the percent ionization. Additionally, Le Chatelier's principle states that a decrease in concentration of the solution will shift the equilibrium towards the formation of more ions, further promoting ionization.
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