Here we have 2 atoms of Na, 1 of C, and 3 of O, which is why we multiply the atomic weights by those numbers.
Na = 22.989770 * 2 = 45.97954 g/mol
C = 12.0107 * 1 = 12.0107 g/mol
O = 15.9994 * 3 = 47.9982 g/mol
If we sum these three products, we get a total of 105.98844 g/mol. This is the molecular weight of Na2CO3. Then, we divide:
45.97954 / 105.98844 = .4338 = 43.38%
12.0107 / 105.98844 = .1133 = 11.33%
47.9982 / 105.98844 = .4529 = 45.29%
Hope that helps.
Sodium: 43.382%
Carbon: 11.332%
Oxygen: 45.286%
Sodium: 32,370 %
Sulfur: 22,575 %
Oxygen: 45,055 %
The percent composition of lithium in LiOH is: 29,21 %.
Can you be more specific? Percent composition is usually the percent of an element in a compound.
The percent composition of ethanol is: - C: 52,13 % - O: 34,74 % - H: 13,13 %
The percent composition of manganese dichoride (MnCl2) is: - Mn: 44 % - Cl: 56 %
The percent composition for CuBr2 is: Cu= 28.45% Br= 71.55%
NaCl is sodium chloride and Na2SO4 is sodium sulfate; chemicals with different composition or structure have different chemical and physical properties.
The percent composition of lithium in LiOH is: 29,21 %.
Can you be more specific? Percent composition is usually the percent of an element in a compound.
Percent composition is usually expressed as a percent by mass, but in the case of gases and vapors, it is often expressed as a percent by volume.
Add up the compound's molar mass: Na=2(23), S=1(32), O=4(16). Sum is 142. Oxygen's part of that total is 64 (16x4). Percent is part/total, so 64/142 = 0.4507 = 45.1%.
The percent composition of ethanol is: - C: 52,13 % - O: 34,74 % - H: 13,13 %
The percent composition of manganese dichoride (MnCl2) is: - Mn: 44 % - Cl: 56 %
The percent composition of nitrous oxide is: - N: 63,649 % - O: 36,351 %
what is the composition of dextrose 5%
The percent composition for CuBr2 is: Cu= 28.45% Br= 71.55%
note: NOT percent composition.
71%