50% AA and 50% Aa
The genotype of the father is certainly OO (because blood type O is recessive). The genotype of the mother however can be AO or AA (both give blood type A). The baby will have a combination of the genes from the mother and the father (one of each) and so: - If the genotype of the mother is AA and the genotype of the father is OO, the baby will certainly have AO as genotype and has therefore blood type A. -If the genotype of the mother is AO and the genotype of the father is OO, the baby can have AO or OO as genotype. AO results in blood type A and OO in blood type O (50% chance).
The genotype of the father is certainly OO (because blood type O is recessive). The genotype of the mother however can be AO or AA (both give blood type A). The baby will have a combination of the genes from the mother and the father (one of each) and so: - If the genotype of the mother is AA and the genotype of the father is OO, the baby will certainly have AO as genotype and has therefore blood type A. -If the genotype of the mother is AO and the genotype of the father is OO, the baby can have AO or OO as genotype. AO results in blood type A and OO in blood type O (50% chance).
The genotype of the man is A negative/O negative inheriting the A neg from his mother and O negative from his father. [Father's genotype is B positive/O negative. Mother's genotype is B positive/A negative.]
The mothers will because the father is the dominant.
This depends entirely on the genotype of the parents. The probability of getting a specific genotype is the probability of getting the correct allele from mother (1/2) multiplied by the probability of getting the correct allele from father (1/2) multiplied by the number of ways this can occur. The probability of getting a phenotype, if the phenotype is dominant, is the sum of the probability of getting two dominant alleles, and the probability of getting one dominant allele. If the phenotype is recessive, the probability is equal to the probability of getting two recessive alleles.
If the mother's genotype is AA, the child can be A+ or A- If the mother's genotype is AO, the child can be A+, A-, O+, or O- Most likely A+
A genotype is decided from two alleles. One of these alleles comes from the father, and one comes from the mother. Thus it should be clear that the genotype can be different from both parents. For instance, suppose the father has genotype AA, and the mother has genotype aa. In this case, the child will have genotype Aa, which neither parent has.
The mother will produce two types of gametes: IA and IO (mother is A) The father is AB his genotype is IAIB, thus he will produce these kind of gametes: IA and IB Four combinations are possible IA from Mother and IA from Father: The child has genotype IAIA and he has blood group A IO from Mother and IA from Father: The child has genotype IAIO and he has blood group A IA from Mother and IB from Father: The child has genotype IAIB and he has blood group AB IO from Mother and IB from Father: The child has genotype IBIO and he has blood group B Thus the phnotypic ratio is blood group A:B:AB = 2:1:1
The mother would have to be type A. Father has genotype (0,0) Mother would need to have genotype (A,0) - fenotype (blood group) = A
The mother is genotype AB, the father is either genotype BO or BB. If the father is genotype BO, the children can be genotype AB, AO, BB, or BO. This results in children with phenotype blood types of: AB, A, or B. If the father is genotype BB, the children can be genotype AB, AB, BB, or BB. This results in children with phenotype blood types of: AB or B.
The mother is genotype AB, the father is either genotype BO or BB. If the father is genotype BO, the children can be genotype AB, AO, BB, or BO. This results in children with phenotype blood types of: AB, A, or B. If the father is genotype BB, the children can be genotype AB, AB, BB, or BB. This results in children with phenotype blood types of: AB or B.
The mothers genotype is either OO++ or OO+-. If it is the former, then the child cannot be B-, so the mother has to be OO+-. The father is able to be either BB++, BB+-, BO++, or BO+-. If he is BB++ or BO++, then he cannot father a child to be B- by a OO+- mother. If he is either BB+- or BO+-, then it is entirely possible for he and an OO+- mother to have a child with phenotype B-. If the father is BB+- the probability is 25%. If he is BO+-, then the probability is 6.25%.