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1Hz is unit of frequency,which is equals to one cycle per second........................
....................................................................................................shashi
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∙ 13y ago
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∙ 12y agoCalculate 1 / 0.1. The answer will be in seconds.
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∙ 14y agoIf the frequency of the signal is ' F ' kilohertz, then the period is (1/F) milliseconds.
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∙ 9y ago1 Hz (hertz) is also known as 1 cycle per second. It means that some periodic event repeats once every second. Often used for waves.
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∙ 14y agoi sec
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What would be the minimum sampling interval needed for reconstructing a signal where the highest frequency is 1 kHz?
The Nyquist frequency for a signal with a maximum bandwidth of 1 KHz is 500 Hz, however that will lead to aliasing unless perfect filters are available. The Nyquist rate for a signal with a maximum bandwidth of 1 KHz is 2 KHz, so the answer to the question is 2 KHz, or 500 microseconds.
What factors can negatively affect a radio signal with a frequency of 200 KHz?
Electricity, Heat, Natural obstacles during daylight hours
What is the frequency of tsop 1738?
38 kHz
One cycle of the signal lasts 0.029 milli seconds.What is the frequency in KHz?
frequency means number of cycles per second. here 1 cycle takes .029 mili sec or .000029 sec so the number of cycles in 1 sec is 1/.000029 = 34482.75 Hz = 34.5 KHz
What is the frequency of the second harmonic if the fundamental frequency is 1000 Hertz?
If the first harmonic of 1 kHz is 2 kHz, then the second harmonic is the odd order harmonic of 3 kHz.
The lowest frequency of a signal is 10 kHz the highest frequency if 1 MHz what is the bandwidth?
BW = (1 MHz - 10 KHz) = (1,000 KHz - 10 KHz) = 990 KHz
What is the frequency deviation if an 2.5 volt 1 khz signal frequency modulates the carrier to cause frequency deviation of 4 khz on increasing the modulating voltage to 10 volts?
If 10 V input causes a frequency shift of 4 kHZ then 2,5v causes a freuency shift of 1 kHz. The input signal frequency of 1 kHz is irelevant.
What would be the minimum sampling interval needed for reconstructing a signal where the highest frequency is 1 kHz?
The Nyquist frequency for a signal with a maximum bandwidth of 1 KHz is 500 Hz, however that will lead to aliasing unless perfect filters are available. The Nyquist rate for a signal with a maximum bandwidth of 1 KHz is 2 KHz, so the answer to the question is 2 KHz, or 500 microseconds.
What is the period of a wave with a frequency of 4 kHz?
Since period is the reciprocal of frequency, i.e Period = 1/frequency: Frequency = 4 kHz = 4000 cycles/sec Period = 1/(4000 cycles/sec) = 1 sec/4000 cycles = 0.00025 sec/cycle
What is the period of a wavelength with a frequency of 0.50 kHz?
Period = 1 / (frequency) = 1 / 500 = 0.002 second = 2 milliseconds
What is the period of the wave motion for a wave with a frequency of 0.50 kHz?
Period = reciprocal of frequency = 1 / (500) = 0.002 second
How is the intelligence signal modulated in the carrier?
If the intelligence signal striking a microphone was doubled in frequency from 1 kHz to 2 kHz with constant amplitude, (fc) would change from 1 kHz to 2 kHz. Because the intelligence amplitude was not changed, however, the amount of frequency deviation above and below fc will remain the same. On the other hand, if the 1 kHz intelligence frequency were kept the same but its amplitude were doubled, the rate of deviation above and below fc would remain at 1 kHz, but the amount of frequency deviation would double.
What is the pulse repetition period if the pulse repetition frequency is 1 kHz?
0.001
What is the frequency in Hz and kHz if the period of oscillation is 7.5 ms?
Frequency = 1/period1/7.5 x 10-3 = 1331/3 Hz = 2/15 KHz
What is the bandwidth of a signal that ranges from 40KHz to 4 MHz?
Solution Let fh is the highest frequency and fl is the lowest frequency. Bandwidth = fh - fl = 4000 - 40 KHz = 3960 KHz = 3.96 MHz
What is pitch period?
The pitch period of a signal is the fundamental period of the signal, or in other words, the time interval on which the signal repeats itself. The pitch frequency is the inverse of the pitch period, which is the fundamental frequency of the signal.
What is the period of the wave motion for a wave with a frequency of 0.48 kHz?
0.48 KHz = 480 HzPeriod = 1/frequency = 1/480 = 0.0020833 second (rounded) = 21/12 milliseconds
