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Power dissipated is always Volts times Amps.
W= V*I
because of ohm's law, V=I*R, you can substitute either the voltage or amperage with the other value;
W= V^2/R or
W= I^2*R.
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A 5 ohm resistor a 10 ohm resistor and a 15 ohm resistor are connected in series to a 120 volt power source. What is the amount of current flowing between the 5 ohm resistor and the 10 ohm resistor?
The current would be about 20 volts.
2 resistors unequal value are in parallel. Would the power dissipated by the resistor with larger ohmic value be greater than the power dissipated by the resistor of lesser value?
No, because the power dissipated in a resistor is proportional to the square of the current through the resistor but only directly proportional to the resistance of the resistor (I^2 * R) and the current through the lower value resistor will be higher than the current through the higher value resistor, the lower value resistor will usually dissipate more power.
How Determine the power dissipated by the resistor?
Power dissipated by the resistor = I^2 * R or V^2 / R, where R = its resistance value, I = the current in the resistor, and V = the voltage drop across the two terminals of the resistor. You need to measure or find the information of either I (using an ammeter) or V (a voltmeter).
What is the power dissipated by a 10 ohm resistor with 20 volts supply?
A 10 ohm resistor across a 20 volt source has 2 amps flowing through it. A 20 volt source providing 2 amps is producing 40 watts. Voltage is Resistance times AmperesWatts is Voltage times AmperesAlternative AnswerDivide the square of the voltage by the resistance.
What is the power dissipated a resistor with a current of 0.02 amps and a resistance of 1000 ohms?
P = I^2 x R] P = 0.2^2 x 100 P = 4 W
Power dissipated in an 800 ohm's resistor connected to a 230V supply is?
66W 230/800= 0,2875. 230= 66w
What is the power dissipated by a parallel resistor of 100 ohms with a 40v power source?
You may find it helpful to use Ohm's law and the definition of electrical power.
Calculate the power used in 2ohm resistor in each what circuits- 1 a 6V battery in series wid 1ohm and 2ohm resistors 2 a 4V battery in parallel wid 12ohm and 2ohm resistors?
1). 6V battery, 1-ohm resistor, 2-ohm resistor, all in series:Total resistance = 3 ohms.Current in the loop = 6/3 = 2 amperesPower dissipated by the 2-ohm resistor - I2R = 8 watts.2). 4V battery, 12-ohm resistor, 2-ohm resistor, all in parallelThe 12-ohm resistor is irrelevant.4 volts across the 2-ohm resistor.Power dissipated by the 2-ohm resistor = E2/R = 8 watts.
A 100 ohm resistor is placed across a 100v power source what is the power?
Power dissipated in a resistance = E2/R = (100)2/100 = 100 watts.
What is the formula of power being dissipated in a resistor?
Voltage times current. You obtain current from the division of voltage and resistance, so: I[A] = U[V] / R[ohm] and P[W] = U[V] * I[A] it follows, that P[W] = U[V] * (U[V] / R[ohm]) = U[V] ^ 2 * R[ohm] So, voltage squared divided by resistance will give you the power that will be dissipated in a resistor. Whether the resistor will take that abuse is up to its power dissipation rating, however.
What power is dissipated if 800v is applied across a 10 ohm resistor?
The power dissipated by a 10 ohm resistor with 800v across it is 64 kw.Ohm's law: current is voltage divided by resistancePower law: power is voltage times current, so power is voltage squared divided by resistanceDon't even think about trying this. 64 kw is a lot of power. The resistor will probably explode, or catch fire. At best, the 80 amps required will trip your circuit breaker, if you are lucky.
How much power will be dissipated by a 9 ohm resistor if 9 volts are applied across it?
P = (E2)/R = 81/9 = 9 watts
If 2 resistors or resistance 10 ohm and 5 ohm resp r connected in parallel which will get more heated?
The 5 Ohm resistor will have more current passing through it than the 10 ohm resistor. Since the resistors are in parallel the Voltage across each resistor is the same. Power or the amount of heat in terms of the question can be derived from Power = Voltage * Current. Ohm's law tells us that the current flowing through a resistor is equal to the Voltage across the resistor divided by the resistance. The formula for power is then the Voltage * Voltage / Resistance. Since V^2 / 10 is smaller than V^2 / 5 we know that the 5 ohm resistor will always have more power dissipated than the 10 ohm resistor.
When a 3 ohm resistor draws a current of 4 A when hooked up to a battery of unknown voltage what is the battery's voltage and what is the power dissipated by the resistor?
Voltage can be calculated using Ohm's Law:Voltage = Current (A) x Resistance (Ω)Voltage = 4A x 3Ω = 12 VoltsTherefore, the battery is a 12 Volts.The power dissipated is Voltage x CurrentPower = 4A x 12V = 48 Watts
A 120 ohm resistor a 60 ohm resistor and a 40 ohm resistor are connected in parallel to a 120 volt power source. What is the current running through the 120 ohm resistor?
1amp
What is the power dissipated in the resistor?
Power dissipated is always Volts times Amps. W= V*I because of ohm's law, V=I*R, you can substitute either the voltage or amperage with the other value; W= V^2/R or W= I^2*R.
A 5 ohm resistor a 10 ohm resistor and a 15 ohm resistor are connected in series to a 120 volt power source. What is the amount of current flowing between the 5 ohm resistor and the 10 ohm resistor?
The current would be about 20 volts.
