p=i square x r = 500ma * 500ma = .25 * 4.7k = 1175 watts
1,175 watts. Which isn't very feasible As it infers a voltage of 2350 Volts across the resistor. Pls recheck you numbers and resubmit
The power generated in a resistor is converted into heat. and that can be power which is converted into heat is the product of the voltage across the resistor and, current passing through the resistor. or the product of square of the current and the resistance offered by the resistor.
No, because the power dissipated in a resistor is proportional to the square of the current through the resistor but only directly proportional to the resistance of the resistor (I^2 * R) and the current through the lower value resistor will be higher than the current through the higher value resistor, the lower value resistor will usually dissipate more power.
It depends on the voltage applied across it. But the maximum current is limited by the power-rating of the resistor (power divided by the square of the voltage).
Four times as much.
The current can't be calculated from the information given in the question.The power rating of a resistor is the maximum power it can dissipate before it overheatsand its resistance possibly changes permanently. The power rating is not the amount ofpower it always dissipates.So, all we really know about the resistor in the question is that its resistance is 21 ohms.And all we can say about the current through it is:Current through the resistor = (voltage between the ends of the resistor) divided by (21).
.205 watts or 205 mw
The power lost in a resistor is(the current through the resistor) times (the resistance) watts. That's the same thing as(the voltage across the resistor)/(the resistance)watts.
1amp
A typical resistor will burn out when it dissipates power in excess of double its power dissipation rating for an extended period of time. The power dissipated by a resistor is equal to I2R or E2/R, where E = the voltage across the resistor I = the current through the resistor R = the resistance of the resistor
POWER=VI. V=voltage I= current
I don't know what the parallel circuit has to do with it. You've onlygiven me a resistor and the current through it.When 0.03A of current passes through a 1,000Ω resistor, the resistordissipates energy at the rate of 0.9 watt.