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The pressure can be calculated using the Ideal Gas Law.

PV = nRT

n = moles = m / M = 32 g / 32 g per mol = 1.00 mole

P = ( n ) ( R ) ( T ) / ( V )

P = ( 1.00 mol ) ( 0.08206 atm - L / mol - K ) ( 303 K ) / ( 22.0 L )

P = 1.13 atm = 115 kPa <--------[ Answer ]

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Q: What is the pressure exerted by 32 g of diatomic oxygen gas in a 22.0L container at 303K?
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