A) 1/16
the answer is half since it can be a boy or girl so half time half is quarter
Being born with six fingers is actually a dominant trait and the probability of the children would be 75% with six fingers and 25% with five fingers if both parents were heterozygous for that trait. If both parents were homozygous dominant for that trait then there is a 100% probability of the children being born with six fingers.
X linked diseases when recessive are only present in female children when both parents have the disease. If the mother is only a carrier of the disease then each male child would have a 50% probability of having the disease, but no female children would be affected (50% would be carriers). Hemophilia is an example of a recessive X linked genetic defect: http://www.answers.com/main/ntquery?s=hemophilia&gwp=13
These are independent events, so the probability of both of them happening would be the probability of one multiplied by the probability of the other. According to insurance odds, the probability of an average golfer getting a hole in one in any given round is 1/3,125. The probability of being struck by lightning is 1/576,000. Thus the probability of both of these things happening is 1/(3,125 x 576,000) = 1/1,800,000,000 or one in 1.8 billion.
Caused by defects in both copies of the gene that codes for an enzyme called galactose-1-phosphate uridyl transferase (GALT). There are 30 known different mutations in this gene that cause GALT to malfunction.
the answer is half since it can be a boy or girl so half time half is quarter
Both are inherited (genetic) disorders
The probability is1 - [Prob(No children) + Prob(1 child, a girl) + Prob(2 children, both girls) + Prob(3 children, all girls) + ...]Not all relevant information is readily available.
Galactosemia II is caused by defects in both copies of the gene that codes for an enzyme called galactokinase (GALK). The frequency of occurrence of galactosemia II is about one in 100,000-155,000 births.
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes. A family of 4 is a family of two parents and two children. The probability that both children are girls is 0.2334
There is no simple answer.First of all, the probability of boys is 0.517 not0.5.Second, the probabilities are not independent.If you choose to ignore these important facts, then the answer is 2/3.
They are both measures of probability.
1-2 children will be affected causing long life disability.
Being born with six fingers is actually a dominant trait and the probability of the children would be 75% with six fingers and 25% with five fingers if both parents were heterozygous for that trait. If both parents were homozygous dominant for that trait then there is a 100% probability of the children being born with six fingers.
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That probability is the product of the probabilities of the two individual events; for example, if event A has a probability of 50% and event B has a probability of 10%, the probability that both events will happen is 50% x 10% = 5%.
The probability that he will not win both games is 0.58