Zinc and Nitric acid react to produce Zinc nitrate, Water and Nitrogen Mono Oxide if the Nitric acid is Dilute...
3Zn + 8HNO3 = 3Zn[No3]2 + 4H20 + 2NO
The equation is 4 Zn + 10 HNO3 -> 4 Zn(NO3)2 + N2O + 5 H2O.
no reaction because Cu is below Zn at electrochemical series ,so Cu can't take Zn away from its salts
Zn + 2HCl --> ZnCl2 + H2
4Zn + 10HNO3 (very dilute) --> 4 Zn(NO3)2 + N2O + 5 H2OZn + 4 HNO3 (Conc) --> Zn(NO3)2 + 2 NO2 + 2H2OZn + 2HNO3(aq) -> Zn(NO3)2(aq) + H2(g)
KNO3 and H2O are the products
The equation is 4 Zn + 10 HNO3 -> 4 Zn(NO3)2 + N2O + 5 H2O.
no reaction because Cu is below Zn at electrochemical series ,so Cu can't take Zn away from its salts
Zn + 2HCl --> ZnCl2 + H2
4Zn + 10HNO3 (very dilute) --> 4 Zn(NO3)2 + N2O + 5 H2OZn + 4 HNO3 (Conc) --> Zn(NO3)2 + 2 NO2 + 2H2OZn + 2HNO3(aq) -> Zn(NO3)2(aq) + H2(g)
KNO3 and H2O are the products
HNO3 + H2O ---> (H3O)+ + (NO3)- Only thing i dont remember is if the arrow is double (<-->). If the acid is potent then the arrow is single. But i think in this case it is potent.
Nitric acid plus zinc oxideNitricoxide
Zn + CuBr2 = Cu + ZnBr2
NaOH + HNO3 -----> NaNO3 + H2O
The chemical reaction is:ZnO + 2 HNO3 = Zn(NO3)2 + H2Adding more HNO3 has no effect.
Zn(NO3)2+ NiO
NaClO + HNO3 --- NaNO3 + HCl + Cl2