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if the objects distance travelled and time is given then speed=distance/time eg- distance travelled 50 mtrs time taken 5 seconds speed 50/5 =10m/s velocity=u(initial velocity 0 for free falling objects) + at(acceleration x time)
By finding the distance the car has travelled , in meters, in a specific time , in seconds , you get the speed of the car in meter per second Then , Speed = Distance Travelled/Time Taken
98 meters (322 feet) per second.
take g = 10 m/s^2 , u = 0 in all cases ,measured from same datum s=(10*t^2)/2 if t = 1 second then s = 5 metres if t = 2 seconds then s = 20 metres (2* time = 4*distance) if t = 3 seconds then s = 45 meters (3* time = 9*distance) if t = 4 seconds then s = 80 meters (4* time = 16 * distance) but distance travelled between secs metres 0-1.......5 1-2.... 15 2-3.... 25 3-4..... 35
9.8 meters/second2 x 10 seconds = 98 meters/second.
Multiply by a value in seconds, that way you find out the distance. The distance will be in metres which will be travelled in a certain amount of seconds
if the objects distance travelled and time is given then speed=distance/time eg- distance travelled 50 mtrs time taken 5 seconds speed 50/5 =10m/s velocity=u(initial velocity 0 for free falling objects) + at(acceleration x time)
distance travelled (feet) / time taken (seconds)
By finding the distance the car has travelled , in meters, in a specific time , in seconds , you get the speed of the car in meter per second Then , Speed = Distance Travelled/Time Taken
The distance travelled, measured in miles divided by the time taken, measured in seconds.
Distance travelled from a velocity / time graph can be calculated from area under graph, say area under (v/t) graph from 0 - 1 seconds = distance travelled after 1 second, then do 0 - 2 seconds, 0 - 3 etc for set of data for distance / time graph
Mass doesn't affect this equation, if its falling from rest at an acceleration (a) of 10 m/s2 the distance travelled (s) in 7 seconds (t) is resolved by the equation: . s = 0.5 * a * t2 s = 0.5 * 10 * 49 s = 245 metres
It depends on how long (time) you are travelling at 20 kilometres per second. Distance = speed x time Say you travelled for 10 seconds then your distance travelled will be 200 km. Every one minute (60 seconds) you will travel 1200 km.
0.7848 meter
It depends on what it of distance is being used. A million million kilometres is 6684 astronomical units, which is the distance travelled by light in 3.3 million seconds, or 5½ weeks.
120 km/h = 120,000m/hr = 33.333 m/s Distance travelled in 50 seconds = 33.333 * 50 = 1666.666 metres Tunnel length = distance travelled - train length - 1666.666 - 135 = 1531.666metres
If air resistance can be ignored, the distance in meters is 4.9t2. Note that 4.9 is half the numerical value of Earth's acceleration (9.8 meters per second square).