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O2
CH4+O2 --- CO2+H2O... All that's missing - is the number 2 before the water molecule... CH4+O2 --- CO2+2H2O
The combustion of a hydrocarbon yields carbon dioxide and water. CH4 + 2O2 ---> CO2 + 2H2O
exothermic
The balanced equation is: CH4 + 2 O2 → CO2 + 2 H2O
O2
The chemical reaction is: CH4 + 2O2 --> 2H2O + CO2 CO2 is the carbon dioxide.
O2
CH4+O2 --- CO2+H2O... All that's missing - is the number 2 before the water molecule... CH4+O2 --- CO2+2H2O
CH4 + 2O2 --> CO2 + 2(H2O), the products are CO2 and H2O
The combustion of a hydrocarbon yields carbon dioxide and water. CH4 + 2O2 ---> CO2 + 2H2O
I assume you were looking to balance the reaction: CH4 + 2O2 --> CO2 +2H2O
exothermic
A combustion reaction.
The hydrocarbons in the fuel react with oxygen to form CO2 plus water (H2O). The simplest hydrocarbon is methane which is the biggest part of natural gas, formula CH4. So CH4 + 2O2 ---- CO2 + 2H2O
No. Argon does not form ions. CH4 is the simplest alkane and is called methane.
Ch4 + 2o2 -> co2 + 2h2o This site is " making capitalization corrections " again. Those letters are all capitals.