O2
I assume you were looking to balance the reaction: CH4 + 2O2 --> CO2 +2H2O
Unbalanced CH4 + O2 = H2O + CO2 Balanced CH4 + 2O2 = 2H20 + CO2
The balanced chemical equation for the reaction is: CH4 + 2O2 -> CO2 + 2H2O Using the molar masses of CH4 and O2, we can calculate the moles present in 24g of CH4 and 96g of O2. From there, we can determine the limiting reactant and the amount of product formed.
The combustion equation typically refers to the chemical reaction of a fuel with oxygen to produce heat, light, and products such as carbon dioxide and water. A general combustion equation for a hydrocarbon fuel like methane (CH4) can be written as: CH4 + 2O2 -> CO2 + 2H2O + heat.
The equation for a complete combustion reaction of CH4 is : CH4 + 2 O2 = CO2 + 2 H2O, showing that one mole of carbon dioxide is formed for each mole of CH4 burned. Therefore, the answer is 44 moles of CO2 formed.
The oxidizing agent in the reaction CH4 + 2O2 → CO2 + 2H2O is oxygen (O2). Oxygen is the substance that is gaining electrons and causing the methane (CH4) to oxidize.
The product in the reaction of CH4 + 2O2 => CO2 + 2H2O is carbon dioxide (CO2) and water (H2O).
I assume you were looking to balance the reaction: CH4 + 2O2 --> CO2 +2H2O
ch4 + 2o2 → co2 + 2h2o
ch4 + 2o2 → co2 + 2h2o
Unbalanced CH4 + O2 = H2O + CO2 Balanced CH4 + 2O2 = 2H20 + CO2
candle
The chemical reaction is: CH4 + 2O2 --> 2H2O + CO2 CO2 is the carbon dioxide.
A combustion reaction.
this is an exotermic reaction
The balanced chemical equation for the reaction CH4 + 2O2 → CO2 + 2H2O shows that 1 molecule of CH4 reacts with 2 molecules of O2 to produce 1 molecule of CO2 and 2 molecules of H2O. This equation ensures that the number of atoms of each element is the same on both sides of the reaction arrow.
A combustion reaction is a reaction that burns. The equation that represents a combustion reaction is CH4 + 2O2 reacts to yield CO2 + 2H2O.