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What is the balanced equation for methane burns oxygen to form water and carbon diooxide?
Unbalanced CH4 + O2 = H2O + CO2 Balanced CH4 + 2O2 = 2H20 + CO2
CH4 plus O2 CO2 plus H2O?
I assume you were looking to balance the reaction: CH4 + 2O2 --> CO2 +2H2O
Which is the oxidizing agent in the reaction CH4 2O2- CO2 H20?
Oxygen (O2) is the oxidizing agent in this reaction, as it gains electrons during the reaction to form water (H2O).
In the reaction of aluminum metal and oxygen gas aluminum oxide is formed How many moles of O2 will react with 2.0 moles Al?
In the reaction 4 moles of aluminum will react with 3 moles of oxygen to form 2 moles of aluminum oxide. Since we have 2.0 moles of aluminum, we would need (2.0 mol Al) x (3 mol O2 / 4 mol Al) = 1.5 moles of O2 to react with it.
Balance this equation CH4 plus O2 equals CO2 plus H2O?
The combustion of methane can be balanced in the following manner. One molecule of CH4 plus two molecules of O2 produces one molecule of CO2 plus one molecule of H2O.
When 3.05 of ch4 is mixed with 5.03 moles of o2 the limiting reactants is?
The balanced chemical equation for the reaction between CH4 and O2 is as follows: CH4 + 2O2 -> CO2 + 2H2O By comparing the moles of CH4 and O2 given, you can see that O2 is the limiting reactant because it will be completely consumed before all of the CH4 can react.
Why does methane undergo oxidation?
Methane , CH4 , is a fuel that can react with O2 to yield CO2, H2O, and heat. CH4 (g) + O2 (g) ----> CO2 (g) + 2 H2O (g) + Heat
If 2.8 moles of CH4 react with 3 moles of O2 what is the limiting reagent?
To determine the limiting reagent, we need to compare the amount of each reactant to their stoichiometric coefficients in the balanced equation. The balanced equation for the combustion of CH4 with O2 is: CH4 + 2O2 -> CO2 + 2H2O. From the given amounts, we can see that O2 is in excess, so CH4 is the limiting reagent.
What mass of oxygen is required to completely react with 20 grams of CH4?
To calculate the mass of oxygen required to react with 20 grams of CH4, we first need to write and balance the chemical equation for the reaction. The balanced equation for the combustion of CH4 is: CH4 + 2O2 → CO2 + 2H2O This equation tells us that 1 mole of CH4 reacts with 2 moles of O2. The molar mass of CH4 is 16 g/mol. Therefore, 20 grams of CH4 is equal to 20/16 = 1.25 moles CH4. So, 1.25 moles of CH4 would require 2.50 moles of O2. The molar mass of O2 is 32 g/mol. Therefore, the mass of O2 required would be 2.50 moles * 32 g/mol = 80 grams.
How many molecules of oxygen 2 are needed to react with which molecule of methane CH4?
To react completely with one molecule of methane (CH4), two molecules of oxygen (O2) are needed. This is because the balanced chemical equation for the combustion of methane is CH4 + 2O2 → CO2 + 2H2O. Each molecule of methane requires two molecules of oxygen to form carbon dioxide and water.
3g of H2 react with 29g of O2 to give water The maximum amount of H2O formed is?
The balanced chemical equation for the reaction is 2H2 + O2 -> 2H2O. Using stoichiometry, we find that 3g of H2 will react completely with 24g of O2 to form 18g of H2O. Therefore, the maximum amount of H2O formed when 3g of H2 reacts with 29g of O2 is 18g.
If you start with 32 grams of CH4 and react it with O2 to form 88 grams CO2 and 72 grams H2O. How much O2 in grams was consumed?
128 g of oxygen are needed.
What is the balanced equation of CH4 plus O2 arrow CO2H2O?
The balanced equation is: CH4 + 2 O2 → CO2 + 2 H2O
When 85.0 g of CH4 are mixed with 160 g of O2 the limiting reactant is?
When 85.0 g of CH4 are mixed with 160. g of O2 the limiting reactant is __________. CH4 + 2O2 → CO2 + 2H2O
How do you balance the equation for CH4 O2 yield CO2 H2O?
The balanced chemical equation for the reaction CH4 + 2O2 → CO2 + 2H2O shows that 1 molecule of CH4 reacts with 2 molecules of O2 to produce 1 molecule of CO2 and 2 molecules of H2O. This equation ensures that the number of atoms of each element is the same on both sides of the reaction arrow.
What is the limiting reactant in combustion of methane is 2.8 moles of methane and 5 moles of oxygen?
Methane reacts with oxygen in the following way. CH4 + 3 O2 --> CO2 + 4 H2O. If 5 moles of oxygen react with 2.8 moles of methane, only 1.67 moles of methane would be consumed because of the molar ratio 1:3. This would produce 1.67 moles of carbon dioxide and 6.67 moles of water.
How many grams of oxygen form when each quantity of reactant completely reacts. 2 KClO3 (s) plus 2 KCl(s) 3O2 (g)?
The balanced chemical reaction equation says that you get 3 moles of O2.m O2 = ( n O2 ) ( M O2 )m O2 = ( 3 mol O2 ) ( 32.00 g O2 / mol O2 = 96 g O2
