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What is the volume of a 24.7 mol gas sample that has a pressure of .999 ATM at 305 K?
Use the ideal gas law, PV=nRT, in which P= pressure, V= volume, n= number of moles, R= the gas constant, and T= temperature. In this problem you know V, T, R, and n. What you are trying to figure out is the P. P= Unknown V= 35.0 L n= 6.50 moles R= .082057 L ATM/mol K T= 305 K PV= nRT P35.0=6.50(.082057)305 P= 4.65 ATM
First, get the molar mass of CCl4, which is carbon tetrachloride. According to the periodic table, carbon has an atomic mass of 12 and chlorine is 35.5, but there's 4 of them, so multiply that by 4. 35.5(4)+12=154grams/mole. If you have 2.5 moles, then it's 154x2.5=305 grams.
it'S GALLIUM... CHECK REFERENCE TABLE S ..
305 k
the pistons are the same diameter. no they are not the same diameter, the bore on a 305 is smaller than a 350
put it over 100 and make into a mixed number Ex) 305%= 305/100 = 3 5/100
Yes, 305 is divisible by 305. =)
305 = 305/1
Since the numbers after the decimal point go up to the thousandths position, .305 can be written as 305/1000. Simplifying this gives 61/200. So as a mixed number, 1.305 can be written as 1 and 61/200, or as an improper fraction, as 261/200.
305.
305%
The factors of 305 are: 1 5 61 305
305-236 = 69
The factors of 305 are: 1, 5, 61, 305
5All Factors of 305:1, 5, 61, 305
1,5,61,and 305