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What is the temperature of 9 moles of an ideal gas in a 35 liter container at 14 atm pressure?
JasonBroughmangp3044
Use the ideal gas law, PV=nRT, in which P= pressure, V= volume, n= number of moles, R= the gas constant, and T= temperature. In this problem you know V, T, R, and n. What you are trying to figure out is the P.
P= Unknown
V= 35.0 L
n= 6.50 moles
R= .082057 L ATM/mol K
T= 305 K
PV= nRT
P35.0=6.50(.082057)305
P= 4.65 ATM
Wiki User
∙ 12y ago
Wiki User
∙ 10y agoThis is an ideal gas law problem, PV=nRT, where p = 14 atm, V = 35 L, n = 9 mol, R = 0.082 L atm/mol K.
Rearrange the equation to solve for T:
T=(PV)/(nR)
T=(14 atm x 35 L)/(9 mol x 0.082 L atm/mol K) = 700 K if your teacher is counting significant figures, 664 K if she isn't.
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What will the pressure inside the container become if the piston is moved to the 1.80 L rm L mark while the temperature of the gas is kept constant?
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What is the temperature of 9 moles of an ideal gas in a 35 liter container at 14 atm pressure-?
This looks suspiciously like a homework question! Temp of 8 mol of ideal gas in a 32 L container at 12 atm pressure? pV = 12 * 32 = 384 L.atm nRT = 8 * 0.082 * T = 0.656 * T L.atm T = 384/0.656 = ~516 K That should provide the template for your answer!
a container of an ideal gas is at a constant volume what occurs when the volume of the contianer is doubled from 1 liter to 2 liters?
The volume doubles
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