xenon
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Any element that is a gas will uniformly fill a closed 2.0 liter container at STP, or, actually, at any condition.
A 1-gram sample of a noble gas, such as helium, in a sealed 1-liter container will occupy the container completely and uniformly. The noble gas atoms are non-reactive and have low mass, allowing them to distribute evenly across the container due to their high kinetic energy and lack of attractive intermolecular forces.
The partial pressure of oxygen in a 2 liter container depends on the concentration of oxygen present in the container. If you know the concentration of oxygen in the container, you can use the ideal gas law to calculate the partial pressure. The formula is: partial pressure = concentration of oxygen x gas constant x temperature.
ANY closed cylinder of 4.0 litre will contain the same number of molecules of ANY gas as the 4.0 liter closed cylinder containing O2 gas at the SAME temperature and pressure, since then the volume only depends on the number of molecules, not on the kind of molecules of the gasses concerned
To prepare a 0.5 M glucose solution in 1 liter of water, you would need to dissolve 90.08 grams of glucose in enough water to make up the total volume of 1 liter. Start by weighing out 90.08 grams of glucose, add it to a container, and then add enough water to make the total volume up to 1 liter.
It depends on the type of gasoline, and other factors such as temperature and pressure, but gasoline has an approximate density of 737.22 kilogram/cubic meter. 737.22 kilogram/cubic meter = 0.73722 kilogram/liter = 737.22 gram/liter 42.4 liters * 0.73722 kilograms/liter = 31.258 kilograms or since you wanted grams, not kilograms... 42.4 liters * 737.22 gram/liter = 31258 grams(http://forum.onlineconversion.com/showthread.php?t=1114)
A 1-gram sample of a noble gas, such as helium, in a sealed 1-liter container will occupy the container completely and uniformly. The noble gas atoms are non-reactive and have low mass, allowing them to distribute evenly across the container due to their high kinetic energy and lack of attractive intermolecular forces.
There is most likely a more efficient way to do this, but this is the best I can do for now.Notation: ( x , y ) where x is the amount of water in the 5-liter container and y is the amount of water in the 7-liter container1. Fill the five-liter container ( 5 , 0 )2. Pour the five-liter container into the seven-liter container ( 0 , 5 )3. Fill the five-liter container ( 5 , 5 )4. Fill the seven-liter container with the five-liter container, leaving 3 liters in the five-liter container ( 3 , 7 )5. Pour out the seven-liter container ( 3 , 0 )6. Pour the five-liter container into the seven-liter container ( 0 , 3 )7. Fill the five-liter container ( 5 , 3 )8. Fill the seven-liter container with the five-liter container, leaving 1 liter in the five-liter container ( 1 , 7 )9. Pour out the seven-liter container ( 1 , 0 )10. Pour the five-liter container into the seven-liter container ( 0 , 1 )11. Fill the five-liter container ( 5 , 1 )12. Pour the five-liter container into the seven-liter container ( 0 , 6 )
You don't have to find the volume ! If gas is put into a closed container, it fills it. The volume of gas in a one liter tank is one liter.
all of it - the air would expand to fit the entire container.
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You have to have something else to build the 4 liters into. Call it The Tub.Fill the 5.Pour the 5 into the 3.That leaves 2 liters in the 5.Pour them into The Tub. You now have 2 liters in The Tub.Empty the 3.Fill the 5.Pour the 5 into the 3.That leaves 2 liters in the 5.Pour them into The Tub. You now have 4 liters in The Tub.QEDYou do not have a TUB, it is not in the problem.Fill the 5 liter containerPour it into the 3 liter container leaving 2 liters in the 5 liter containerEmpty the 3 liter containerPour the 2 liters from the 5 liter container into the 3 liter containerFill the 5 liter containerFill the remainder of the 3 liter container from the 5 liter containerSince the 3 liter container already had 2 liters in it, one liter from the 5 liter container will fill it leaving 4 liters in the 5 liter container.Solved
As illustrated in the 1995 movie Die Hard 3 (Bruce Willis, Samuel K. Jackson), you can measure out exactly 7 liters in the following manner:Fill the 5 liter container, then use that 5 liters to fill the 3 liter container.Dump out the 3 liter container.What was left in the 5 gallon container is 2 liters. Pour this into the 3 liter container.Fill the 5 liter container again.You now have 7 liters : 5 in the large container and 2 in the smaller one.
The pressure measured in a closed two-liter container would depend on factors such as the temperature and the amount of gas or liquid inside the container. If the container is sealed and there is no chemical reaction occurring inside, the pressure would remain constant at the equilibrium pressure of the system.
The equivalent of 1 container to liters depends on the specific type of container being referenced, as containers come in various sizes. For example, a standard shipping container is typically around 28,300 liters, while a common beverage container like a liter bottle holds exactly 1 liter. To provide a precise answer, the specific dimensions or type of container must be specified.
Notes: There is most likely a more efficient way to do this, but this is the best I can do for now.Notation: ( x , y ) where x is the amount of water in the 5-liter container and y is the amount of water in the 7-liter container1. Fill the five-liter container ( 5 , 0 )2. Pour the five-liter container into the seven-liter container ( 0 , 5 )3. Fill the five-liter container ( 5 , 5 )4. Fill the seven-liter container with the five-liter container, leaving 3 liters in the five-liter container ( 3 , 7 )5. Pour out the seven-liter container ( 3 , 0 )6. Pour the five-liter container into the seven-liter container ( 0 , 3 )7. Fill the five-liter container ( 5 , 3 )8. Fill the seven-liter container with the five-liter container, leaving 1 liter in the five-liter container ( 1 , 7 )9. Pour out the seven-liter container ( 1 , 0 )10. Pour the five-liter container into the seven-liter container ( 0 , 1 )11. Fill the five-liter container ( 5 , 1 )12. Pour the five-liter container into the seven-liter container ( 0 , 6 )
a liter